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\(3^{200}=9^{100}>4^{100}\\ 5^{200}=25^{100}< 64^{100}=4^{300}\\ 6^{50}=36^{25}>7^{25}\\ 8^{40}=64^{20}>10^{20}\\ 16^{20}=256^{10}>32^{10}\)
tick mik nha!!
3200=9100>41005200=25100<64100=4300650=3625>725840=6420>10201620=25610>3210
S=1+3+3^2+3^3+...+3^10
3.S=3+3^2+3^3+3^4+...+3^11
3.S-S=(3+3^2+3^3+3^4+...+3^10)-(1+3+3^2+3^3+...+3^10
3.S-S=3+3^2+3^3+3^4+...+3^11-1-3-3^2-3^3-...-3^10
S=3^11-1
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{22}.3^7-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)
\(=\frac{3.8}{2^2}\)
\(=\frac{3.2^3}{2^2}\)
\(=3.2\)
\(=6\)
Chúc bạn học giỏi nha!!!
K cho mik vs nhé
a) Ta có: \(19\cdot64+36\cdot19\)
\(=19\cdot\left(64+36\right)\)
\(=19\cdot100=1900\)
b) Ta có: \(150-\left[10^2-\left(14-11\right)^2\cdot2700^0\right]\)
\(=150-\left[100-3^2\cdot1\right]\)
\(=150-91\)
\(=69\)
c) Ta có: \(22^3-\left(1^{10}+8\right):3^2\)
\(=22^3-\left(1+8\right):3^2\)
\(=22^3-9:9\)
\(=22^3-1\)
\(=10647\)
d) Ta có: \(59-\left[90-\left(17-8\right)^2\right]\cdot1^{4514}\)
\(=59-\left[90-9^2\right]\cdot1\)
\(=59-\left(90-81\right)\)
\(=59-9=50\)
e) Ta có: \(7^2-36:3^2\)
\(=7^2-36:9\)
\(=49-4=45\)
\(\frac{\frac{1}{9}-\frac{5}{6}-4}{\frac{7}{12}-\frac{1}{36}-10}\)
\(=\frac{\frac{2}{18}-\frac{15}{18}-\frac{72}{18}}{\frac{21}{36}-\frac{1}{36}-\frac{360}{36}}\)
\(=\frac{\frac{-85}{18}}{\frac{-340}{36}}\)
\(=\frac{-85\cdot\frac{1}{18}}{-340\cdot\frac{1}{36}}\)
\(=\frac{-85\cdot\frac{2}{36}}{-340\cdot\frac{1}{36}}\)
\(=\frac{-85\cdot\left(\frac{2}{36}\div\frac{1}{36}\right)}{-340\cdot\left(\frac{1}{36}\div\frac{1}{36}\right)}\)
\(=\frac{-85\cdot2}{-340}\)
\(=\frac{-170}{-340}\)
\(=\frac{-1}{-2}\)
\(=\frac{1}{2}\)
\(36:9+2^2.3-10\)
\(=4+4.3-10\)
\(=4+12-10\)
\(=16-10\)
\(=6\)
Bài làm
36:9+22.3-10
= 4 + 4.3 - 10
= 4 + 12 - 10
= 6
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