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1) 1/3 x 1/2 x 3/7 = 3/42 = 1/14
2) 5/4 x 1/3 +1/7 = 5/12 + 1/7 = 35/84 + 12/84 = 47/84
3) 8 x ( 8/9 - 2/3 ) = 8 x 2/9 = 16/9
4) 5/6 x 48/20 x 1/2 = 240/240 = 1
5) ( 2/5 + 3/4 ) + 8 = 23/20 + 8 = 23//20 + 160/20 = 183/20
6) 10 x ( 1/2 - 1/5 ) = 10 x 3/10 = 10/1 x 3/10 = 30/10 = 3
\(\dfrac{2}{13}\times12=\dfrac{2}{13}\times\dfrac{12}{1}=\dfrac{24}{13}\)
\(1-\dfrac{5}{6}=\dfrac{1}{1}-\dfrac{5}{6}=\dfrac{6}{6}-\dfrac{5}{6}=\dfrac{1}{6}\)
\(\dfrac{5}{7}+\dfrac{1}{3}=\dfrac{15}{21}+\dfrac{7}{21}=\dfrac{22}{21}\)
1: \(=\dfrac{1}{3}\cdot\dfrac{3}{7}\cdot\dfrac{1}{2}=\dfrac{1}{7\cdot2}=\dfrac{1}{14}\)
2: =5/12+1/7
=35/84+12/84=47/84
3: =8(8/9-6/9)
=8*2/9=16/9
4: \(=\dfrac{5}{12}\cdot\dfrac{12}{5}=1\)
5: =16/5+6
=16/5+30/5=46/5
6: =10*1/2-10*1/5
=5-2=3
8/12 + 9/12 = 17/12
12/15 - 5/15 = 7/15
4 x 8/3 = 32/3
1/8 x 3 = 3/8
5 x 2 = 10
2/5 x 1/4 = 2/20 = 1/10
\(\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{17}{12};\dfrac{4}{5}-\dfrac{1}{3}=\dfrac{12}{15}-\dfrac{5}{15}=\dfrac{7}{15}\\ 4\times\dfrac{8}{3}=\dfrac{32}{3};\dfrac{1}{8}\times3=\dfrac{3}{8}\\ 5:\dfrac{1}{2}=5\times\dfrac{2}{1}=10;\dfrac{2}{5}:4=\dfrac{2}{5}\times\dfrac{1}{4}=\dfrac{2}{20}=\dfrac{1}{10}\)
a) S
⇒ \(\dfrac{3}{5}+\dfrac{1}{4}=\dfrac{12}{20}+\dfrac{5}{20}=\dfrac{17}{20}\)
b) \(\)Đ
c) Đ
d) S
⇒ \(\dfrac{3}{4}:\dfrac{4}{9}=\dfrac{3}{4}\times\dfrac{9}{4}=\dfrac{27}{16}\)
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\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)
\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)
\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)
\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)
3/4+5/6 = 19/12
9/10-1/5 = 9/10 - 2/10 = 7/10
5/3 : 1/5 x 3/2 = 5/3 x 5 x 3/2 = 75/6 = 25/2
3/4+5/6=18/24+20/24=38/24=19/12
9/10-1/5 = 9/10-2/10=7/10
5/3 : 1/5 x 3/2=25/3x3/2=25/2