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a) 6x = 19 + 15 = 34
=> x = 34 : 6 = 17/3
b) 3x + 2 = 8
=> 3x = 8 - 2 = 6
=> x = 6 : 3 = 2
c) 12x - 33 = 135
=> 12x = 135 + 33 = 168
=> x = 168 : 12 = 14
d) 100x + \(\frac{100.101}{2}\) = 5750
<=> 100x + 5050 = 5750
=> 100x = 5750 - 5050 = 700
=> x = 700 : 100 = 7
Bài 2:Tìm x
a.6x-15=19 b. 3x+2=20+(-12)
6x=19+15 3x+2=8
6x=34 3x=6
x=34:6 x=6:3
x=17/3 x=2
Vậy x=17/3 Vậy x=2
c) 12x - 33=5.3^3 d) ( x+1 ) + ( x+2 ) + ... + ( x+100 ) = 5750
12x-33=135 Vì cứ 1 số hạng lại có 1x
12x=135-33 Vậy từ 1 đến 100 có số số hạng là:
12x=102 (100-1):1+1=100(số)
x=102:12 Tổng dãy số là:
x=17/2 (100+1)x100:2=5050
Vậy x=17/2 Do đó có 100x ta có:
( x+1 ) + ( x+2 ) + ... + ( x+100 ) = 5750
(x+x+...+x)+(1+2+...+100)=5750
100x+5050=5750
100x=700
x=7
Vậy x=7
a)6x-15=19
6x=19+15
6x=34
x=34/6
b)3x+2=20+(-12)
3x+2=8
3x=8-2
3x=6
x=6/3
x=2
c)12x-33=5*33=5*27=135
12x=135+33
12x=168
x=168/12
x=14
d)(x+1)+(x+2)+...+(x+100)=5750
(x+x+....+x)+(1+2+3+....+100)=5750
100x+5050=5750
100x=5750-5050
100x=700
x=700/100
x=7
a: Ta có: \(7x+25=144\)
\(\Leftrightarrow7x=119\)
hay x=17
b: Ta có: \(33-12x=9\)
\(\Leftrightarrow12x=24\)
hay x=2
c: Ta có: \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
hay x=31
d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)
\(\Leftrightarrow5\left(726-3x\right)=2175\)
\(\Leftrightarrow726-3x=435\)
\(\Leftrightarrow3x=291\)
hay x=97
e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x+5\right)=18\)
\(\Leftrightarrow2x+5=23\)
\(\Leftrightarrow2x=18\)
hay x=9
Bài 6:
\(21,251+6,058+0,749+1,042\)
\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)
\(=22+7,1\)
\(=29,1\)
___________________
\(1,53+5,309+12,47+5,691\)
\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)
\(=14+11\)
\(=25\)
5:
a: =>x/17=5/17
=>x=5
b; =>6+x=7/11*33=21
=>x=15
c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)
=>3x+36=86-2x
=>5x=50
=>x=10
d: \(\dfrac{x}{5}< \dfrac{3}{7}\)
=>x<3/7*5
=>x<15/7
f: 15/26+x/16=46/52
=>x/16=23/26-15/26=8/26=4/13
=>x=4/13*16=64/13
a.219 - 7(x+1) = 100
7(x+1) = 219 - 100
7(x+1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
b. (3x - 6 ) . 3 = 36
3x - 6 = 36 : 3
3x - 6 = 12
3x = 12 + 6
3x = 18
x = 18 : 3
x = 6
c.716 - ( x-143) = 659
x-143 = 716 - 659
x-143 = 57
x = 57 + 143
x = 200
b. 30 - [4(x-2)+15] = 3
4(x-2) + 15 = 30 - 3
4(x-2)+15 = 27
4(x-2) = 27 - 15
4(x-2) = 12
x-2 = 12 : 4
x-2 = 3
x = 2 + 3 = 5
e.[(8x - 12) : 4] .33 = 36
[(8x - 12) : 4] . 27 = 729
(8x - 12) : 4 = 729 : 27 = 27
8x - 12 = 27 . 4 = 108
8x = 108 + 12 = 120
x = 120 : 8 = 15
a) \(\Leftrightarrow7\left(x+1\right)=119\\ \Leftrightarrow x+1=17\\ \Leftrightarrow x=16\)
b) \(\Leftrightarrow9\left(x-2\right)=36\\ \Leftrightarrow x-2=4\\ \Leftrightarrow x=6\)
c) \(\Leftrightarrow x-143=57\\ \Leftrightarrow x=200\)
d) \(\Leftrightarrow4\left(x-2\right)+15=27\\ \Leftrightarrow4\left(x-2\right)=12\\ \Leftrightarrow x-2=3\\ \Leftrightarrow x=5\)
e) \(\Leftrightarrow\left(2x-3\right).4:4=3^3\\ \Leftrightarrow2x-3=27\\ \Leftrightarrow2x=24\\ \Leftrightarrow x=12\)
`x+(-1/2)=3`
`=>x= 3-(-1/2)`
`=>x= 3+1/2`
`=>x= 6/2+1/2`
`=>x=7/2`
`---------`
`x-3/4 =4/3`
`=>x= 4/3 + 3/4`
`=>x= 16/12+9/12`
`=>x= 25/12`
`------------`
`3/4+(x-1/2)=5/6`
`=>x-1/2=5/6-3/4`
`=>x-1/2=20/24 - 18/24`
`=>x-1/2=2/24`
`=>x-1/2=1/12`
`=>x= 1/12 +1/2`
`=>x= 1/12+ 6/12`
`=>x=7/12`
a) (x+1)+(x+2)+(x+3)+...+(x+100)
=100.x+(1+2+3,..+100)
=100.x+100.101/2
=>
100x+101.50=5750
100x=5750-5050=700
x=7
b) 433 - (15x + 70) = 33
(15x + 70) = 433 - 33
(15x + 70) = 400
15x = 400 - 70
15x = 330
x = 330 : 15
x = 22
c) (13 + x ) . 8 = 136
(13 + x ) = 136 : 8
(13 + x ) = 17
x = 17 - 13
x = 4
d) 3x - 35 = 40
3x = 40 + 35
3x = 75
x = 75 : 3
x = 25
các bạn ơi hãy k cho mk và kban các bạn nhé!!!! I love you!!!! thank for reading. chúc các bạn học giỏi
( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750
x x 100 + ( 1 + 2 + 3 + ... + 100 ) = 5750
x x 100 + 5050 = 5750
x x 100 = 5750 - 5050
x x 100 = 700
x = 700 : 100
x = 7
Mấy cái dưới dễ tự làm ik chứ bn
e: =>-40+3+33+40-x=47
=>36-x=47
=>x=-11
f: =>x(x-3)(11-x)(11+x)=0
hay \(x\in\left\{0;3;11;-11\right\}\)
g: =>-62-38-x+2x=-100
=>x-100=-100
hay x=0
\(33+\left(3\times-1\right)^5=10^0\)
\(\Rightarrow\left(3\times-1\right)^5=10^0-33\)
\(\Rightarrow\left(3\times-1\right)^5=1-33\)
\(\Rightarrow\left(3\times-1\right)^5=-32\)
\(\Rightarrow\left(3\times-1\right)^5=\left(-2\right)^5\)
\(\Rightarrow3\times-1=-2\)
\(\Rightarrow3\times=-1\)
\(\Rightarrow\times=\frac{-1}{3}\)
33+(3x-1)5 = 100
=> 33+(3x-1)5 = 1
33+(3x-1)=1
3x-1=1- 33
3x-1= -32
3x = -31
x = \(\frac{-31}{3}\)
Vậy .........