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1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
` 1/2 + 3/4 - 5/6 = 6/12 + 9/12 - 10/12 = 5/12`
` ( 5/6 + 3/8) xx 2/7 = ( 15/24 + 9/24) xx 2/7 = 29/24 xx 2/7 = 29/84`
` ( 7/6 - 3/4) : 3/5 = ( 14/12 - 9/12) : 3/5 = 5/12 : 3/5 = 5/12 xx 5/3 = 25/36`
` 6/7 xx 2/3 : 5/7 = 6/7 xx 2/3 xx 7/5 = 4/5`
1, =4/9 x (3/7 + 2 x 4/7) - 1/9 - 3/9
= 4/9 x 1 - 1/9 - 3/9 = 0
2, = ( 22/5 x 5/22 ) x 12
= 1 x 12 = 12
Bài 2:
\(=\left(\dfrac{1}{5}+\dfrac{4}{5}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{1}{4}+\dfrac{1}{4}\right)=2+\dfrac{1}{2}=\dfrac{5}{2}\)
Bài 1:
150/120+15/27=5/4+5/9=45/36+20/36=65/36
42/49+56/84=6/7+2/3=9/21+14/21=23/21
Bài 2:
a: 2/6x5/3=10/18=5/9
b: 11/9x5/10=55/90=11/18
c: 3/9x6/8=1/3x3/4=1/4
d: 4/9x12/16=48/144=1/3
e: 25/15x6/7=5/3x6/7=30/21=10/7
f: 6/10x15/20=90/200=9/20
Bài 1
4/5 x 6/7= 24/35
2/9 x 1/2= 2/18= 1/9
1/2 x 8/3= 8/6= 4/3
7/9 x 6/5= 42/45= 14/15
8/7 x 5/9= 40/63
10/11 x 22/15= 220/165= 4/3
Bài 2
2/6 x 5/3= 1/3 x 5/3=5/9
11/9 x 5/10= 11/9 x 1/2= 11/18
3/9 x 6/8= 1/3 x 3/4 =3/12= 1/4
4/9 x 12/16= 4/9 x 3/4= 12/36= 1/3
25/15 x 6/7= 5/3 x 6/7= 30/21= 10/7
6/10 x 15/20= 3/5 x 3/4= 9/20
bài 1:
a)lấy mẫu chung là 12,ta có:4/12+5/12=9/12
câu tiếp bằng 5/9
lấy mẫu chung là 9,ta có:7/9-6/9=1/9
b)MSC:35 kết quả bằng 38/35
MSC:12 kết quả bằng -7/12
MSC:35 kết quả bằng 207/35
c)MSC:24 kết quả bằng 11/12
tương tự bằng 1/6
MSC:24 kết quả bằng 13/24
bài 2
a)x=8/2
b)x=6/7-2/3=4/21
c)x=7/3
bài 1 : chỉ cần quy đồng hai số cùng mẫu là đc
bài 2 : xác định thành phần của x rồi tinh
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
\(a,\dfrac{5}{9}+\dfrac{3}{8}=\dfrac{40}{72}+\dfrac{27}{72}=\dfrac{67}{72}\)
\(b,\dfrac{8}{12}-\dfrac{1}{3}=\dfrac{8}{12}-\dfrac{4}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)
\(c,\dfrac{4}{7}\times\dfrac{5}{2}=\dfrac{20}{14}=\dfrac{10}{7}\)
\(d,\dfrac{5}{11}:\dfrac{15}{22}=\dfrac{5}{11}\times\dfrac{22}{15}=\dfrac{110}{165}=\dfrac{22}{33}\)
\(310+\dfrac{1}{5}=\dfrac{1550}{5}+\dfrac{1}{5}=\dfrac{1551}{5}\)
\(\dfrac{6}{7}-\dfrac{1}{2}=\dfrac{12}{14}-\dfrac{7}{14}=\dfrac{5}{14}\)
\(\dfrac{2}{5}\times\dfrac{1}{4}\times\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)
\(310+\dfrac{1}{5}=\dfrac{1550}{5}+\dfrac{1}{5}=\dfrac{1551}{5}\)
\(\dfrac{6}{7}-\dfrac{1}{2}=\dfrac{12}{14}-\dfrac{7}{14}=\dfrac{5}{14}\)
\(\dfrac{2}{5}\times\dfrac{1}{4}:\dfrac{3}{2}=\dfrac{1}{10}:\dfrac{3}{2}=\dfrac{1}{10}\times\dfrac{2}{3}=\dfrac{1}{15}\)