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a) 3A = 3 + 3^2 + 3^3 + 3^4 + ... + 3^100 + 3^ 101
=> 3A - A = (3 + 3^2 + 3^3 + 3^4 + ... + 3^100 + 3^ 101) - (1 + 3 + 3 ^2 + 3 ^ 3 + ... + 3 ^100)
=> 2A = 3^101 - 1 => A = (3^101 - 1)/2
b) 4B = 4 + 4 ^ 2 + 4 ^3 + 4 ^ 4 + ... + 4 ^ 100 + 4^ 101
=> 4B - B = (4 + 4 ^ 2 + 4 ^3 + 4 ^ 4 + ... + 4 ^ 100 + 4^ 101) - (1 + 4 + 4 ^ 2 + 4 ^3 + 4 ^ 4 + ... + 4 ^ 100 )
=> 3B = 4^101 - 1 => B = ( 4^101 - 1)/2
c) xem lại đề ý c xem quy luật như thế nào nhé.
d) 3D = 3^101 + 3^ 102 + 3^ 103 + ... + 36 150 + 3^ 151
=> 3D - D = (3^101 + 3^ 102 + 3^ 103 + ... + 36 150 + 3^ 151) - (3 ^100 + 3 ^ 101 + 3 ^ 102 + .... + 3 ^ 150)
=> 2D = 3^ 151 - 3^100 => D = ( 3^ 151 - 3^100)/2
a) Có A=\(1+3+3^2+3^3+....+3^{100}\)
\(\Rightarrow\)3A =\(3\left(1+3+3^2+3^3+...+3^{100}\right)\)=\(3+3^2+3^3+3^4+...+3^{101}\)
\(\Rightarrow2A=3+3^2+3^3+....+3^{101}-1-3-3^2-3^3-....-3^{100}=3^{101}-1\)\(\Rightarrow A=\dfrac{3^{101}-1}{2}\)
Bài b/c/d : bn cứ lm tương tự.
a) 23 = 8; 24 = 16; 25 = 32; 26 = 64; 27 = 128; 28 = 256; 29 = 512; 210 = 1024
b) 32 = 9; 33 = 27; 34 = 81; 35 = 243
c) 42 = 16; 43 = 64; 44 = 256
d) 52 = 25; 53 = 125; 54 = 625
c) 62 = 36; 63 = 216; 64 = 1296
a) 23 = 8; 24 = 16; 25 = 32; 26 = 64; 27 = 128; 28 = 256; 29 = 512; 210 = 1024
b) 32 = 9; 33 = 27; 34 = 81; 35 = 243
c) 42 = 16; 43 = 64; 44 = 256
d) 52 = 25; 53 = 125; 54 = 625
e) 62 = 36; 63 = 216; 64 = 1296
HT
\(a,3^6:3^5=3^{6-5}=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right)\cdot\left(7^5:7^4\right)=2^2\cdot7=28\\ d,5^4-2\cdot5^3=5^3\left(5-2\right)=3\cdot5^3=375\)
a) 3^6 : 3^5 = 729 : 243 = 3
b) 5^7 : 5^5 = 78125 : 3125 = 25
c) 14^5 : 2^3 : 7^4 = 537824 : 8 : 2401 = 89
d) 5^4 - 2 * 5^3 = 625 - 2 * 125 = 625 - 250 = 375
\(a,3^6:3^5=3^{6-5}=3^1=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right).\left(7^5:7^4\right)=2^{5-3}.7^{5-4}=2^2.7^1=4.7=28\\ d,5^4-2.5^3=5.5^3-2.5^3=\left(5-2\right).5^3=3.5^3=3.125=375\)
A = 2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90
2A = 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100
2A - A = ( 2^4 + 2^5 + 2^6 + 2^7 + 2^8 + .... + 2^90 + 2^100 ) - ( 2^3 + 2^4+ 2^5+ 2^6 + 2^7 + ... + 2^90 )
A = 2^100 - 2^3
B = 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50
5B = 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51
5B - B = ( 5 + 5^2 + 5^3 + 5^4 + 5^5 + .... + 5^50 + 5^51 ) - ( 1 + 5 + 5^2 + 5^3 + 5^4 + .... + 5^50 )
4B = 5^51 - 1
B = 5^51 - 1 / 4
a=2mu 101 - 2
b= 3 mu 2010 - 1
c=5mu 1999-1
d=4 mu n . 4 -4
a=2+22+...+2100
2a=22+23+24+...+2101
a=2a-a=a
=> a= 22+23+24+..+2101 -(2+2^2+...+2^100)
=>a= 2^101 -2
`A = 2 + 2^2+ ... + 2^2017`
`=> 2A = 2^2 + 2^3 + ... + 2^2018`
`=> 2A - A = (2^2 + 2^3 + ... + 2^2018) - (2 + 2^2 + ... +2^2017)`
`=> A = 2^2018 - 2`
`B = 1 + 3^2 + ... + 3^2018`
`=> 3^2B = 3^2 + 3^4 + ... + 3^2020`
`=> 9B-B =(3^2 + 3^4 + ... + 3^2020) - (1 + 3^2 + ... + 3^2018`
`=> 8B = 3^2020 - 1`
`=> B = (3^2020 - 1)/8`
`C = 5 + 5^2 - 5^3 + ... + 5^2018`
`=> 5C = 5^2 + 5^3 - 5^4 + ... +5^2019`
`=> 5C + C = ( 5^2 + 5^3 - 5^4 + ... 5^2019) + (5 + 5^2 - 5^3 + ... + 5^2018)`
`=> 6C = 55 + 5^2019`
`=> C = (5^2019 + 55)/6`
a: =5-78*32
=5-2496
=-2491
b: \(=6\left(9-6\right)=6\cdot3=18\)
c: \(=46\cdot\dfrac{\left(123-42\right)}{81}=46\)
d: \(=181+3-84+8\cdot25\)
=100+200
=300
e: \(=64\cdot35+140\cdot84-1=2240-1+11760\)
=14000-1
=13999
f: \(=3^3+25\cdot8-1=26+200=226\)
g: \(=3+2^4+1=16+4=20\)
h: \(=36:4\cdot3+2\cdot25-1=27+50-1=27+49=76\)
\(A=4+4^2+...+4^{99}\)
\(\Rightarrow4A=4^2+3^3+...+4^{99}+4^{100}\)
\(\Rightarrow4A-A=4^{100}-4\)
\(\Rightarrow3A=4^{100}-4\Rightarrow A=\frac{4^{100}-4}{3}\)
\(B=5+5^2+...+5^{10}\)
\(5B=5^2+5^3+...+5^{10}+5^{11}\)
\(5B-B=4B=5^{11}-5\Rightarrow B=\frac{5^{11}-5}{4}\)
C đang 6 mũ sao tự nhiên nhảy đâu ra 9 mũ?
Nếu nó là 6 mũ thì làm tương tự như 2 câu trên
\(3^5.4^5\)
\(=\left(3.4\right)^5\)
\(=12^5\)
cảm ơn bn