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a)26 + 5x = 3x + 56
5x – 3x = 56 – 26
2x = 30
x = 30 : 2 = 15
26 + 5x = 3x - 56
5x - 3x = 56 - 26
5x - 3x = 30
2x = 30
x = 30 : 2
x = 15
\(\frac{x+1}{5x}-\frac{1}{3x}=\frac{-26}{5}\)
\(\Leftrightarrow\frac{\left(x-1\right)3-5}{15x}=\frac{-26}{5}\)
\(\Leftrightarrow\frac{3x+3-5}{15x}+\frac{26}{5}=0\Leftrightarrow\frac{3x-2+26.3x}{15x}=0\)
\(\Leftrightarrow\)\(\frac{81x-2}{15x}=0\)
\(\Rightarrow81x-2=0\Rightarrow x=\frac{2}{81}\)
x + 1/5x - 1/3x = -26/5
x(1 + 1/5 - 1/3) = -26/5
13/15x = -26/5
x = -26/5 : 13/15
x = -6
\(x-\frac{1}{3}x+\frac{1}{5}x=\frac{-26}{x}\)
\(x-\frac{5}{15}x+\frac{3}{15}x=\frac{-26}{x}\)
\(x.\left(1-\frac{5}{15}+\frac{3}{15}\right)=\frac{-26}{x}\)
\(x.\left(\frac{15}{15}-\frac{5}{15}+\frac{3}{15}\right)=\frac{-26}{x}\)
\(x.\frac{13}{15}=\frac{-26}{x}\)
\(\frac{13x}{15}=\frac{-26}{x}\)
\(13x.x=-26.15\)
\(13x^2=-390\)
\(x^2=-390:13\)
\(x^2=-30\)
=56.26-56.18-26.56+26.18
=56.26-26.56 +18.(-56+26)
=0+18.-30=-540
b: Ta có: 7x-8=713
nên 7x=721
hay x=103
c: Ta có: x-36:18=12
nên x-2=12
hay x=14
d: Ta có: (x-36):18=12
nên x-36=216
hay x=252
\(26+5x=3x+56\)
\(\Rightarrow5x-3x=56-26\)
\(\Rightarrow2x=30\)
\(\Rightarrow x=30:2\)
\(\Rightarrow x=15\)
Vậy \(x=15\)