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Ta có:
\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{x.\left(x+1\right)}=\frac{432}{15}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{432}{15}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{x+1}=\frac{432}{15}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{1}-\frac{432}{15}=-\frac{139}{5}\)
\(\Rightarrow\left(x+1\right).-139=5\Rightarrow x=\frac{-5}{139}-1=-\frac{144}{139}\)
Có thể bạn đã sai đề.
Bài 4:
a: \(\dfrac{x}{15}=\dfrac{2}{3}\)
=>\(x=15\cdot\dfrac{2}{3}=10\)
b: \(x+\dfrac{-8}{13}=\dfrac{-21}{13}\)
=>\(x-\dfrac{8}{13}=-\dfrac{21}{13}\)
=>\(x=-\dfrac{21}{13}+\dfrac{8}{13}=-\dfrac{13}{13}=-1\)
c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
=>\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{1}{10}+\dfrac{5}{10}=\dfrac{6}{10}=\dfrac{3}{5}\)
=>\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
d: \(\dfrac{3}{4}+\dfrac{1}{4}:x=-3\)
=>\(\dfrac{1}{4}:x=-3-\dfrac{3}{4}=-\dfrac{15}{4}\)
=>\(x=\dfrac{1}{4}:\dfrac{-15}{4}=\dfrac{-1}{15}\)
e: \(\left(\dfrac{2}{3}-x\right)\left(x-\dfrac{1}{4}\right)=0\)
=>\(\left[{}\begin{matrix}\dfrac{2}{3}-x=0\\x-\dfrac{1}{4}=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{1}{4}\end{matrix}\right.\)
f: 0,51-x=-0,35
=>x=0,51-(-0,35)
=>x=0,51+0,35=0,86
Bài 3:
a: \(-\dfrac{1}{2}+\dfrac{5}{6}+\dfrac{1}{3}\)
\(=\dfrac{-3+5+2}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
b: \(\dfrac{-3}{8}+\dfrac{7}{4}-\dfrac{1}{12}\)
\(=\dfrac{-9}{24}+\dfrac{42}{24}-\dfrac{2}{24}=\dfrac{31}{24}\)
c: \(\dfrac{3}{5}:\left(\dfrac{1}{4}\cdot\dfrac{7}{5}\right)\)
\(=\dfrac{3}{5}:\dfrac{7}{20}\)
\(=\dfrac{3}{5}\cdot\dfrac{20}{7}=\dfrac{3\cdot4}{7}=\dfrac{12}{7}\)
d: \(\dfrac{10}{11}+\dfrac{4}{11}:4-\dfrac{1}{8}\)
\(=\dfrac{10}{11}+\dfrac{1}{11}-\dfrac{1}{8}\)
\(=1-\dfrac{1}{8}=\dfrac{7}{8}\)
e: \(\dfrac{-5}{7}+\dfrac{8}{11}+\left(-\dfrac{2}{7}\right)+\dfrac{1}{4}+\dfrac{3}{11}\)
\(=\left(-\dfrac{5}{7}-\dfrac{2}{7}\right)+\left(\dfrac{8}{11}+\dfrac{3}{11}\right)+\dfrac{1}{4}\)
\(=-1+1+\dfrac{1}{4}=\dfrac{1}{4}\)
f: \(\dfrac{2}{7}\cdot\dfrac{5}{13}+\dfrac{2}{7}\cdot\dfrac{6}{13}-\dfrac{2}{7}\cdot1\dfrac{11}{13}\)
\(=\dfrac{2}{7}\cdot\left(\dfrac{5}{13}+\dfrac{6}{13}-1-\dfrac{11}{13}\right)\)
\(=\dfrac{2}{7}\cdot\left(-1\right)=-\dfrac{2}{7}\)
g: \(15,3-21,5-3\cdot1,5\)
=15,3-21,5-4,5
=15,3-26
=-10,7
h: \(2\left(4^2-2\cdot4,1\right)+1.25:5\)
=2(16-8,2)+0,25
=15,6+0,25
=15,85
Sorry sai rồi
Ta phá ngoặc
15 - 15 + x = -x - 34
x = -x - 34
x = 34 : 2
x = 17
-17 = 17 - 34 ( 17 là vì âm của âm = dương )
15-(15-x) = x- ( 25 + 9 )
Ta phá ngoặc
15 - 15 - x = x - 34
0 - x = x - 34
-x = x - 34
=> x = 34 : 2
x = 17
Thay vào
-17 = 17 - 34
\(15-2.x=25\)
\(2.x=15-25=-10\)
\(x=\left(-10\right)\div2=-5\)
\(31-\left(17+x\right)=18\)
\(\left(17+x\right)=31-18=13\)
\(x\) \(=13-17=-4\)
15−2.x=2515−2.x=25
2.x=15−25=−102.x=15−25=−10
x=(−10)÷2=−5x=(−10)÷2=−5
31−(17+x)=1831−(17+x)=18
(17+x)=31−18=13(17+x)=31−18=13
xx =13−17=−4
25+(x-5)=123-(15-123)
=>x-5+25=123-15+123
=>x+20=246-15=231
=>x=231-20=211
a) Ta có: \(x-12=\left(-9\right)-15\)
\(\Rightarrow x-12=-24\)
\(\Rightarrow x=-12\)
b) \(2-x=17-\left(-5\right)\)
\(\Rightarrow2-x=22\)
\(\Rightarrow x=2-22\)
\(\Rightarrow x=-20\)
c) \(11-\left(15+11\right)=x-\left(25-9\right)\)
\(\Rightarrow-15=x-16\)
\(\Rightarrow x=1\)
d) \(x-\left(17-x\right)=x-7\)
\(\Rightarrow x-17+x=x-7\)
\(\Rightarrow x+x-x=-7+17\)
\(\Rightarrow x=10\)
e) \(9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Rightarrow9-25=7-x-25-7\)
\(\Rightarrow-16=-25-x\)
\(\Rightarrow x=-9\)
g) \(x-13=21-x\)
\(\Rightarrow x+x=21+13\)
\(\Rightarrow2x=34\)
\(\Rightarrow x=17\)
a, x - 12 = ( -9 ) - 15
x - 12 = -24
x = -24 + 12
x = -12
b, 2 - x = 17 - ( -5 )
2 - x = 22
x = 2 - 22
x = -20
c, 11 - ( 15 + 11 ) = x - ( 25 - 9 )
11 - 26 = x - 16
-15 = x - 16
x = -15 + 16
x = 1
d, x - ( 17 - x ) = x - 7
x - 17 + x = x - 7
x + x - 17 = x - 7
x + x - x = -7 + 17
x = 10
e.9 - 25 = ( 7- x ) - ( 25 + 7 )
-16 = ( 7 - x ) -32
7 - x = -32 + 16
7 - x = 16
x = 7 - 16
x= -9
g, x - 13 = 21 - x
x + x = 21 + 13
2x = 44
x = 44 : 2
x=22
\(a.13.\left(78+22\right)=13.100=1300\)
\(b.25.70+28.25+25.2=25.\left(70+28+2\right)=25.100=2500\)
\(c.\dfrac{15.3.14.2.19}{19.14.15}=6\)
\(d.\dfrac{132.70.60}{12.35.20}=\dfrac{11.12.35.2.20.3}{12.35.20}=66\)
Nếu = 0 thì chỉ có 1 trường hợp
! x - 1 ! = 0
=> x - 1 = 0
x = 0 + 1
x = 1
|x - 1| = 0
x = 0 + 1
x = 1
mik ko biết cách khác
k mik nha bn
( x + 15 ) - 97 = 215
x + 15 = 215 + 97
x + 15 = 312
x = 312 - 15
x = 297
A
<=>x+15=215+97=312
<=>x =312-15
<=>x =297
B
<=>2x=238-84=154
<=>x =154:2
<=>x =77
C
<=>x-93=7
<=>x =7+93
<=>x =100
25 + 15 + x = -35
40 + x = -35
x = -35 - 40
x = -75
40+x=(-35)
x=(-75)