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\(\frac{17}{8}+\frac{28}{15}-\frac{8}{15}=\frac{17}{8}+\frac{4}{3}=\frac{83}{24}=3\frac{11}{24}\)
=> chọn a
\(\dfrac{15}{24}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{5}{8}-\dfrac{3}{8}-\dfrac{1}{6}=\dfrac{1}{4}-\dfrac{1}{6}=\dfrac{1}{12}\)
\(\dfrac{7}{13}\cdot\dfrac{5}{24}\cdot\dfrac{39}{75}=\dfrac{39}{13}\cdot\dfrac{5}{75}\cdot\dfrac{7}{24}=3\cdot\dfrac{1}{15}\cdot\dfrac{7}{24}=\dfrac{35}{24}\)
a) 3/5x7/8:10/9=21/40:10/9=189/400
b) 3 2/7x2 1/4:1 2/5=23/7x9/4:7/5=207/28:7/5=1035/196
c) 6/9+24/15+12/9+6/15=34/15+12/9+6/15=18/5+6/15=4
d) 3 2/9-( 1 5/8+1 2/9 )=29/9-(13/8+11/9)=29/9-205/72=3/8
A) \(\frac{7}{8}+1-\frac{3}{4}\)
\(=\frac{7}{8}-\frac{6}{8}+1\)
\(=\frac{1}{8}+1\)
\(=\frac{9}{8}\)
B)\(\frac{15}{24}-\frac{3}{8}-\frac{1}{6}\)
\(=\frac{15}{24}-\frac{9}{24}-\frac{4}{24}\)
\(=\frac{1}{12}\)
\(1\dfrac{1}{3}\times1\dfrac{1}{8}\times1\dfrac{1}{15}\times1\dfrac{1}{24}\times1\dfrac{1}{35}\)
= \(\dfrac{4}{3}\times\dfrac{9}{8}\times\dfrac{16}{15}\times\dfrac{25}{24}\times\dfrac{36}{35}\)
= \(\dfrac{4\times9\times16\times25\times36}{3\times8\times15\times24\times35}\)
= \(\dfrac{1\times2\times2\times25\times36}{1\times2\times15\times24\times35}\)
= \(\dfrac{4\times25\times36}{30\times24\times35}\)
= \(\dfrac{1\times25\times36}{30\times6\times35}=\dfrac{1}{7}\)
Sai rồi nhé! Từ dấu bằng thứ 2 xuống dấu bằng thứ 3 bạn làm sao đc z?
`#3107.101107`
`(24*15 + 15)/(8*3+1)`
`= (15* (24+1))/(24 + 1)`
`= (15*25)/25`
`= 15/1`
`=15`