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Ta có:
\(\frac{2}{7}S=\frac{2}{7}.\left(\frac{7}{3.5}+\frac{7}{5.7}+...+\frac{7}{2015.2017}\right)\)
\(\Rightarrow\frac{2}{7}S=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{2015.2017}\)
\(\Rightarrow\frac{2}{7}S=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2015}-\frac{1}{2017}\)
\(\Rightarrow\frac{2}{7}S=\frac{1}{3}-\frac{1}{2017}=\frac{2014}{6051}\)
\(\Rightarrow S=\frac{2014}{6051}:\frac{2}{7}=1\frac{998}{6051}\)
S = \(\frac{7}{3.5}+\frac{7}{5.7}+\frac{7}{7.9}+....+\frac{7}{2015.2017}\)
2S = \(7\).( \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{2015.2017}\))
2S = \(7.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{2015}-\frac{1}{2017}\right)\)
2S = \(7.\left(\frac{1}{2}-\frac{1}{2017}\right)\)
\(2S=7.\frac{2015}{4034}\)
\(S=\frac{7.2015}{4034.2}=1,74826475\)
\(2\frac{1}{6}+x:\frac{6}{7}=-75\%\)
\(\frac{13}{6}+x:\frac{6}{7}=-\frac{3}{4}\)
\(x:\frac{6}{7}=-\frac{3}{4}-\frac{13}{6}=-\frac{35}{12}\)
\(x=-\frac{35}{12}x\frac{6}{7}=\frac{5}{2}\)
vậy \(x=\frac{5}{2}\)
\(2\frac{1}{6}+x\div\frac{6}{7}\)\(=-75\%\)
\(\frac{13}{6}+x\div\frac{6}{7}\)\(=-0,75\)
\(\frac{13}{6}+x\div\frac{6}{7}\) \(=-0,75\)
\(\frac{13}{6}+x\) \(=-0,75\times\frac{6}{7}\)
\(\frac{13}{6}+x\) \(=\frac{-9}{14}\)
\(x\) \(=\frac{-9}{14}-\frac{13}{6}\)
\(x\) \(=\frac{-59}{21}\)
Tk cho mk nhé!
a)7^3.25-7^3.18
=7^3.(25-18)
=7^3.7
=7^3+1
=7^4
b)2^4.15-[173-(14-9)^2]
=16.15-[173-5^2]
=240-[173-25]
=240-148
=92
c)53.147+53^2+47.200
=53.147+53.53+47.200
=53.(147+53)+47.200
=53.200+47.200
=200.(53+47)
=200.100
=20000
d)36:{280:[240-(95+3.25)]}
=36:{280:[240-(95+75)]}
=36:{280:[240-170]}
=36:{280:70}
=36:4
=9
Z = { -2 ; -1 ; 0 ; 1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 7 ; 8 ; 9}
=>(x . 3 -8)=7 . 4
=>x . 3-8 =28
=.x.3 = 28+8
=>x.3= 36
=>x=36:3
=>x=12
(x . 3 - 8):4 = 7
x.3 - 8 = 7 . 4 = 28
x.3 = 28 + 8 = 36
x = 36:3 = 12
trần thị thông thảo : Cách làm thế nào bạn , cả câu b và c nữa nhé
-2/3 + 3/7.x = 19/21
3/7.x = 19/21 - -2/3 ( 19 phần 21 - âm 2 phần 3)
3/7.x = 11/7
x = 11/7 : 3/7
x = 11/3
tk mjk nha
X=11/3