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a: x^3=7^3
=>x^3=343
=>\(x=\sqrt[3]{343}=7\)
b: x^3=27
=>x^3=3^3
=>x=3
c: x^3=125
=>x^3=5^3
=>x=5
d: (x+1)^3=125
=>x+1=5
=>x=4
e: (x-2)^3=2^3
=>x-2=2
=>x=4
f: (x-2)^3=8
=>x-2=2
=>x=4
h: (x+2)^2=64
=>x+2=8 hoặc x+2=-8
=>x=6 hoặc x=-10
j: =>x-3=2 hoặc x-3=-2
=>x=1 hoặc x=5
k:
9x^2=36
=>x^2=36/9
=>x^2=4
=>x=2 hoặc x=-2
l:
(x-1)^4=16
=>(x-1)^2=4(nhận) hoặc (x-1)^2=-4(loại)
=>x-1=2 hoặc x-1=-2
=>x=3 hoặc x=-1
4:
=>(2x+3,5)=7/12*3/14=21/168=1/8
=>2x=1/8-7/2=1/8-28/8=-27/8
=>x=-27/16
5: =>1/3:3x=-21/4
=>3x=-1/3:21/4=-1/3*4/21=-4/63
=>x=-4/189
6: =>2+7/9-3/4(x+1)=7/9
=>2-3/4(x+1)=0
=>3/4(x+1)=2
=>x+1=2:3/4=2*4/3=8/3
=>x=5/3
\(\left(2x+1\right)^3=125\\ \Rightarrow\left(2x+1\right)^3=5^3\\ \Rightarrow2x+1=5\\ \Rightarrow2x=4\\ \Rightarrow x=2.\\ b,\left(2x-1\right)^4=16\\ \Rightarrow\left(2x-1\right)^4=2^4\\ \Rightarrow2x-1=2\\ \Rightarrow2x=3\\ \Rightarrow x=\dfrac{3}{2}.\\ c,6.3^x-2.3^x=36\\ \Rightarrow3^x.\left(6-2\right)=36\\ \Rightarrow3^x.4=36\\ \Rightarrow3^x=9\\ \Rightarrow3^x=3^2\\ \Rightarrow x=2.\\ d,2^{x+1}-2^x=32\\ \Rightarrow2^x.\left(2-1\right)=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5.\)
3x=234—> 243 chứ bạn
3x=243
Vì 35=243
Nên x=5
3x=4096
6x=216
Vì 63=216
Nên x=3
5.3x=405
3x=405:5
3x=81
Vì 34=81
Nên x=4
2x=4
Vì 22=4
Nên x=2
x5=32
Vì 25=32
Nên x=5
x4=81
Vì 34=81 và (-3)4=81
Nên x=3 hoặc x=-3
(x—2)5=243
(x—2)5=35
Nên x—2=3
x=3+2
x=5
(x—1)4=16
(x—1)4=24
Nên x—1 =2 hoặc x—1=-2
x=2+1 hoặc x=-2 +1
x=3 hoặc x=-1
(x+1)3=125
(x+1)3=53
Nên x+1=3
x=3-1
x=1
(x—2)3=64
(x—2)3=43
Nên x—2=4
x=4+2
x=6
(x—1)5=32
(x—1)5=25
==> x—1=5
x=5+1
x=6
\(3^x=243\Rightarrow3^x=3^5\Rightarrow x=5\)
câu thứ 2 mn chịu
\(6^x=216\Rightarrow6^x=6^3\Rightarrow x=3\)
\(5.3^x=405\\ 3^x=405:5\\ 3^x=81\\ \Rightarrow3^x=3^4\\ \Rightarrow x=4\)
\(2^x=4\\ \Rightarrow2^x=2^2\\ \Rightarrow x=2\)
\(x^5=32\\ \Rightarrow x^5=2^5\\ \Rightarrow x=2\)
câu 7 mn ko hỉu
\(x^4=81\\ x^4=\left(+-3\right)^4\\ x=+-3\)
câu 9 mn chịu
\(x^4=x\)
\(\Rightarrow x=1\)
\(\left(2x+1\right)^3=125\)
\(\Rightarrow\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1=4\)
\(\Rightarrow x=4:2=2\)
\(2^{3x}+4=132\)
\(\Rightarrow2^{3x}=132-4=128\)
\(\Rightarrow2^{3x}=2^7\)
\(\Rightarrow3x=7\)
\(\Rightarrow x=7:3=\frac{7}{3}\)
5(x-1)=125-25
5(x-1)=100
x-1=100:5
x-1=20
x=20+1
x=21
12(x-1):3=64+8
12(x-1):3=72
12(x-1)=72.3
12(x-1)=216
x-1=216:12
x-1=18
x=18+1
x=19
(x-1)^3=5^3
=>x-1=5
x=5+1
x=6
Ta có \(1\frac{1}{5}x+\frac{2}{3}x=-\frac{56}{125}\)
<=> \(\frac{6}{5}x+\frac{2}{3}x=-\frac{56}{125}\)
<=> \(\frac{28}{15}x=-\frac{56}{125}\)
<=> \(x=-\frac{2}{15}\)
b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
<=> \(\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=0\)
<=> \(\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
<=> \(\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
<=> x + 100 = 0
<=> x = -100
a. 7/12 - 1/4 : ( -4/11 - x ) = 125%
=> 1/4 : ( -4/11 - x ) = 7/12 - 5/4 = -2/3
=> -4/11 - x = 1/4 : -2/3
=> -4/11 - x = -3/8
=> x = -4/11 - ( -3/8 )
=> x = 1/88
b. 1/2x - 1/3 = 2/3x - 5/6
=> 1/2x - 2/3x = 1/3 - 5/6
=> -1/6x = -1/2
=> x = -1/2 : -1/6
=> x = 3
\(2^x=32=>x=5\)
\(2^{x+1}=32=>x+1=5=>x=4\)
\(x^3=125=>x=5\)
\(\left(x+1\right)^3=125=>x+1=5=>x=4\)
3. x3 = 125 => x = 5
4. (x + 1)3 = 125
(x + 1)3 = 53
=> x + 1 = 5
=> x = 4
t i c k nhé!! 45457474678789886973463125135153152454654657657868768