Question

[Ly Nguyen]

1.Metan ->axetilen ->vinyl axetilen ->buta -1,3-dien->polibutadien 2.Canxicacbua->axetilen ->vinyl clorua ->PVC

Answer 1

[Lê Ng Hải Anh]

1. \(2CH_4\underrightarrow{^{1500^oC,lln}}C_2H_2+3H_2\)

 \(2C_2H_2\underrightarrow{t^o,p,xt}C_4H_4\)

\(CH_2=CH-C\equiv CH+H_2\underrightarrow{t^o,Pd}CH_2=CH-CH=CH_2\)

\(nCH_2=CH-CH=CH_2\underrightarrow{t^o,xt,p}\left(-CH_2-CH=CH-CH_2-\right)_n\)

2. \(CaC_2+2H_2O\rightarrow Ca\left(OH\right)_2+C_2H_2\)

\(CH\equiv CH+HCl\rightarrow CH_2=CHCl\)

\(nCH_2=CHCl\underrightarrow{t^o,p,xt}\left(-CH_2-CHCl-\right)_n\)

Answer 2

[✎﹏ Pain ッ]

1. \(2CH_4\xrightarrow[1500^o]{làm.lạnh.nhanh}CH\equiv CH+3H_2\)

\(CH\equiv CH\xrightarrow[CuCl,NH_4Cl]{t^o}CH_2=CH-C\equiv CH\)

\(CH_2=CH-C\equiv CH+H_2\xrightarrow[Pd,PbCO_3]{t^o}CH_2=CH-CH=CH_2\)

\(nCH_2=CH-CH=CH_2\underrightarrow{t^o,xt,p}\left(-CH_2-CH=CH-CH_2-\right)n\)

2. \(CaC_2+2H_2O\rightarrow Ca\left(OH\right)_2+CH\equiv CH\)

\(CH\equiv CH+HCl\xrightarrow[HgCl_2]{t^o}CH_2=CHCl\)

\(nCH_2=CHCl\underrightarrow{t^o,xt,p}CH_2-CHCl\)