Question

[nguyen ngoc son]

1.giải pt

a)\(\dfrac{16-x}{4}=\dfrac{2x+1}{3}\)

b)(2x+3)(1-3x)=9x\(^2\)-1

c)\(\dfrac{2x}{x+1}+\dfrac{x-1}{x}=\dfrac{2x^2+3x-1}{x^2+x}\)

Answer 1

[khang]

a>16-x/4=2x+1/3

<=>3[16-x)=4(2x+1)

<=>48-3x=8x+8

<=>-3x-8x=8-48

<=>-5x=-40

<=>x=8

Answer 2

[nguyen ngoc son]

trả lời đc 1 câu thì đừng trả lời