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là số nguyên?
\(\dfrac{6n-10}{2n-6}=\dfrac{3\left(2n-6\right)+8}{2n-6}=3+\dfrac{8}{2n-6}\)
\(\Rightarrow2n-6\inƯ\left(8\right)=\left\{\pm1;\pm2;\pm4;\pm8\right\}\)
| 2n-6 | 1 | -1 | 2 | -2 | 4 | -4 | 8 | -8 |
| n | loại | loại | 4 | 2 | 5 | 1 | 7 | -1 |
d, ĐK:\(n+2\ne0\Leftrightarrow n\ne-2\)
\(e,A=2\\ \Leftrightarrow\dfrac{n+9}{n+2}=2\\ \Rightarrow n+9=2n+4\\ \Leftrightarrow n=5\\ A=4\\ \Leftrightarrow\dfrac{n+9}{n+2}=4\\ \Leftrightarrow n+9=4n+8\\ \Leftrightarrow3n=1\\ \Leftrightarrow n=\dfrac{1}{3}\)
\(f,A\in Z\\ \Rightarrow\dfrac{n+9}{n+2}\in Z\\ \Rightarrow\dfrac{n+2+7}{n+2}\in Z\\ \Rightarrow1+\dfrac{7}{n+2}\in Z\)
Để \(A\in Z\Rightarrow\dfrac{7}{n+2}\in Z\Rightarrow7⋮\left(n+2\right)\Rightarrow n+2\inƯ\left(7\right)\)
Ta có bảng:
| n+2 | -7 | -1 | 1 | 7 |
| n | -9 | -3 | -1 | 5 |
Vậy \(n\in\left\{-9;-3;-1;5\right\}\)