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Nửa chu vi hcn là:
\(\dfrac{5}{2}:2=\dfrac{5}{4}\left(m\right)\)
Chiều dài hcn là:
\(\left(\dfrac{5}{4}+\dfrac{1}{4}\right):2=\dfrac{3}{4}\left(m\right)\)
Chiều rộng hcn là:
\(\dfrac{5}{4}-\dfrac{3}{4}=\dfrac{1}{2}\left(m\right)\)
Nửa chu vi hcn là : 5/2 : 2 = 5/4
Chiều dài hcn là : ( 5/4 + 1/4 ) : 2 = 3/4
Chiều rộng hcn là : 5/4 - 3/4 = 1/2
a: 1-1/2=1/2
b: 1-3/10=7/10
c:3-1/3=8/3
d: 4-1/9=35/9
e: 8-2/3=22/3
f: 5-2/5=23/5
a: bằng 1 phần 2
b: bằng 7 phần 10
c: bằng 2 phần 3
d:bằng 35 phần 9
e: bằng 22 phần 3
g: bằng 23 phần 5
chúc bn học tốt
a: \(\dfrac{5}{3}\cdot\dfrac{4}{5}=\dfrac{4}{3}\)
b: \(\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)
c: \(\dfrac{7}{6}\cdot\dfrac{6}{5}=\dfrac{7}{5}\)
d: \(\dfrac{8}{5}\cdot\dfrac{5}{7}=\dfrac{8}{7}\)
e: \(\dfrac{7}{6}\cdot\dfrac{6}{7}=\dfrac{7}{7}=1\)
g: \(\dfrac{9}{5}\cdot\dfrac{5}{2}=\dfrac{9}{2}\)
h: \(\dfrac{4}{3}\cdot\dfrac{3}{5}=\dfrac{4}{5}\)
\(a,\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{4}{13}\times\dfrac{3}{2}=\left(\dfrac{13}{4}\times\dfrac{4}{3}\right)\times\left(\dfrac{2}{3}\times\dfrac{3}{2}\right)=1\times1=1\)
\(b,\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\left(\dfrac{19}{32}+\dfrac{13}{32}\right)=1+1+1=3\\ c,\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\times1=\dfrac{4}{7}\\ d,\dfrac{3}{5}\times\dfrac{7}{9}-\dfrac{3}{5}\times\dfrac{2}{9}=\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)
\(e,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\times1=\dfrac{1}{4}\\ f,\dfrac{7}{9}\times\dfrac{8}{5}\times\dfrac{3}{5}=\dfrac{56}{75}\\ g,\dfrac{2}{5}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{3}{5}=\dfrac{3}{4}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\\ h,\dfrac{2006}{2005}\times\dfrac{3}{4}-\dfrac{3}{4}\times\dfrac{1}{2005}=\dfrac{3}{4}\times\left(\dfrac{2006}{2005}-\dfrac{1}{2005}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\)
a: \(=\dfrac{13}{4}\cdot\dfrac{4}{13}\cdot\dfrac{2}{3}\cdot\dfrac{3}{2}=1\cdot1=1\)
b: \(=\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{6}{7}+\dfrac{1}{7}+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)
c: \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)
d: \(=\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\cdot\dfrac{5}{9}=\dfrac{1}{3}\)
e: \(=\dfrac{1}{4}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\)
a)8/25 ; 9/25 ; 12/25; 24/25
b)7/3 ; 7/9 ;7/8 ; 7/26
c)3/5 ; 9/10; 14/15; 23/30
d)5/9; 11/15 ; 11/18 ;14/15
1965cm2
1965 cm2