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160 - (23 . 52 - 6 . 25)
= 160 - (8 . 25 - 6 . 25
= 160 . [ 25 . (8-6) ]
= 160 . 50
= 8000
\(160-\left[2^3.5^2-6.25\right]\)
\(=160-\left[8.25-6.25\right]\)
\(=160-\left[25.\left(8-6\right)\right]\)
\(=160-\left[25.2\right]\)
\(=160-50\)
\(=110\)
a. \(160 - \left( {{2^3}{{.5}^2} - 6.25} \right)\)
\(\begin{array}{l} = 160 - \left( {8.25 - 6.25} \right)\\ = 160 - 25.\left( {8 - 6} \right)\\ = 160 - 25.2\\ = 160 - 50\\ = 110\end{array}\)
Ta có: 110 = 2.5.11
b. \(37.3 + 225:{15^2}\)
\(\begin{array}{l} = 37.3 + 225:225\\ = 37.3 + 1\\ = 111 + 1\\ = 112\end{array}\)
Ta có: \(112 = 2^4.7\)
c. \(5871:103 - 64:{2^5}\)
\(\begin{array}{l} = 5871:103 - 64:32\\ = 57 - 2 = 55\end{array}\)
Ta có: 55 = 5. 11
d. \(\left( {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8} \right){.5^2} - 850:2\)
\(\begin{array}{l} = \left[ {\left( {1 + 8} \right) + \left( {2 + 7} \right) + \left( {3 + 6} \right) + \left( {4 + 5} \right)} \right]{.5^2} - 850:2\\ = \left( {9 + 9 + 9 + 9} \right){.5^2} - 850:2\\ = {9.4.5^2} - 850:2\\ = {36.5^2} - 425\\ = {36.5^2} - {5^2}.17\\ = {5^2}.\left( {36 - 17} \right)\\ = {5^2}.19=475\end{array}\)
Ta có: \(475 = 5^2.19\)
a: \(160-\left(2^3\cdot5^2-6\cdot25\right)\)
\(=160-\left(8\cdot25-150\right)\)
\(=160-200+150=10=2\cdot5\)
b: \(=111+225:225=112=2^4\cdot7\)
c: \(=57-64:32=57-2=55=5\cdot11\)
d: \(=\left(9\cdot\dfrac{8}{2}\right)\cdot25-425=36\cdot25-425=25=5^2\)
\(160-\left(2^3.5^3-6.25\right)\)
\(=160-8.125+6.25\)
\(=160-1000+150\)
\(=210-1000\)
\(=-790\)
160-(2^3.5^3-6.25)
= 160 - ( 8.125.150 )
= 160 - 150000
= - 149840
160-(23.52-6.25)
=160-(8*25-6*25)
=160-25*(8-6)
=160-25*2
=160-50
=110
Phân tích ra thừa số nguyên tố là:2x5x11
\(\text{56+ 7. (-5)+ (-9). (-2)}\)
\(=56+\left(-35\right)+18\)
\(=39\)
học tốt
\(2\cdot\left(-3\right)^2+\left(-2\right)^3\cdot5\)
\(=2.9+\left(-8\right)\cdot5\)
\(=18-40\)
\(=-22\)
\(B=\dfrac{\left(2^3.5^4.11\right).\left(2.5^2.11^2\right)}{\left(2^2.5^3.11\right)^2}\)
\(\Leftrightarrow B=\dfrac{2^3.5^4.11.2.5^2.11^2}{2^4.5^9.11^2}\)
\(\Leftrightarrow B=\dfrac{2^4.5^6.11^3}{2^4.5^9.11^2}\)
\(\Leftrightarrow B=\dfrac{11}{5^3}\)
\(\Leftrightarrow B=\dfrac{11}{125}\)
Vậy...
\(B=\dfrac{2^4\cdot5^6\cdot11^3}{2^4\cdot5^6\cdot11^2}=11\)
=160- (2^3.5^2^3.5^2)
=160-0
=160
\(160-\left(2^3.5^2-6.25\right)\)
\(=160-\left(8.25-6.25\right)\)
\(=160-\left[25.\left(8-6\right)\right]\)
\(=160-50\)
\(=110\)