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Mình sửa lại đề nè:
\(x+\frac{5}{13}+\frac{10}{26}+\frac{15}{39}+\frac{20}{52}+\frac{40}{104}=\frac{25}{13}\)
\(=x+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}+\frac{5}{13}=\frac{25}{13}\)
\(=x+\frac{5}{13}x5=\frac{25}{13}\)
\(x+\frac{25}{13}=\frac{25}{13}\)
\(x=\frac{25}{13}-\frac{25}{13}\)
\(x=0\)
Chúc bạn học tốt!
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}-\frac{2}{9}\)
\(\frac{x}{27}=\frac{1}{9}\)
\(\frac{x}{27}=\frac{3}{27}\)
\(x=3\)
Ấy nhầm, làm lại nha:
\(\frac{x}{27}-\frac{2}{9}=\frac{6}{18}\)
\(\frac{x}{27}=\frac{6}{18}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{3}{9}+\frac{2}{9}\)
\(\frac{x}{27}=\frac{5}{9}\)
\(\frac{x}{27}=\frac{15}{27}\)
\(x=15\)
Giải:
\(9-3\times\left(x-9\right)=6\)
\(3\times\left(x-9\right)=9-6\)
\(3\times\left(x-9\right)=3\)
\(x-9=3:3\)
\(x-9=1\)
\(x=1+9\)
\(x=10\)
\(4+6\times\left(x+1\right)=70\)
\(6\times\left(x+1\right)=70-4\)
\(6\times\left(x+1\right)=66\)
\(x+1=66:6\)
\(x+1=11\)
\(x=11-1\)
\(x=10\)
\(\dfrac{x}{13}+\dfrac{15}{26}=\dfrac{46}{52}\)
\(\dfrac{x}{13}=\dfrac{23}{26}-\dfrac{15}{26}\)
\(\dfrac{x}{13}=\dfrac{4}{13}\)
\(\Rightarrow x=4\)
\(\dfrac{11}{14}-\dfrac{3}{x}=\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{11}{14}-\dfrac{5}{14}\)
\(\dfrac{3}{x}=\dfrac{3}{7}\)
\(\Rightarrow x=7\)
\(5\times\left(3+7\times x\right)=40\)
\(3+7\times x=40:5\)
\(3+7\times x=8\)
\(7\times x=8-3\)
\(7\times x=5\)
\(x=5:7\)
\(x=\dfrac{5}{7}\)
\(x\times6+12:3=120\)
\(x\times6+4=120\)
\(x\times6=120-4\)
\(x\times6=116\)
\(x=116:6\)
\(x=\dfrac{58}{3}\)
\(x\times3,7+x\times6,3=120\)
\(x\times\left(3,7+6,3\right)=120\)
\(x\times10=120\)
\(x=120:10\)
\(x=12\)
\(\left(15\times24-x\right):0,25=100:\dfrac{1}{4}\)
\(\left(360-x\right):0,25=400\)
\(360-x=400.0,25\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
\(71+65\times4=\dfrac{x+140}{x}+260\)
\(\left(x+140\right):x+260=71+260\)
\(x:x+140:x+260=331\)
\(1+140:x+260=331\)
\(140:x=331-1-260\)
\(140:x=70\)
\(x=140:70\)
\(x=2\)
\(\left(x+1\right)+\left(x+4\right)+\left(x+7\right)+...+\left(x+28\right)=155\)
\(10\times x+\left(1+4+7+...+28\right)=155\)
Số số hạng \(\left(1+4+7+...+28\right)\) :
\(\left(28-1\right):3+1=10\)
Tổng dãy \(\left(1+4+7+...+28\right)\) :
\(\left(1+28\right).10:2=145\)
\(\Rightarrow10\times x+145=155\)
\(10\times x=155-145\)
\(10\times x=10\)
\(x=10:10\)
\(x=1\)
Đều theo cách lớp 5 nha em!
\(\frac{15}{26}+\frac{x}{16}=\frac{46}{52}\)
\(\frac{x}{16}=\frac{46}{52}-\frac{15}{26}\)
\(\frac{x}{16}=\frac{1}{4}\)
4 : 1 = 4
Suy ra x = 4
HkT~
#Wind
A) x/13+15/26=46/52
x/13+15/26=23/26
x/13=23/26-15/26
x/13=4/13
x=4
647-[y:(46+13+54)]=54-32+46
=647-[ y:( 46+13+54) ]=68
=647-[y:113]=68
=647-68
=579
=579x113
=65427
x/13 + 15/26 = 23/26
x/13 = 23/26 - 15/26
x/13 = 8/26
x /13 = 4/13
x = 4
\(\frac{15}{26}+\frac{x}{13}=\frac{46}{32}\)
\(\frac{x}{13}=\frac{46}{32}-\frac{15}{26}\)
\(\frac{x}{13}=\frac{1196}{832}-\frac{480}{832}\)
\(\frac{x}{13}=\frac{716}{832}\)
\(\frac{x}{13}=\frac{179}{208}\)
\(\frac{x}{13.16}=\frac{179}{208}\)
\(\frac{x}{208}=\frac{179}{208}\)
\(x=179\)
chú ý: dấu "." là dấu nhân
ko mình nha