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a, => x= -9. 2
=> x= -18
b, => x= 12. (-4)
=> x=-48
c, => 152-(3x-1)=54
=> (3x-1)= 152- 54= 98
=> 3x= 98+1= 99
=> x = 99:3
=> x = 33
a) -152 - (3x + 1) = (-2).(-3)3
-152 - 3x - 1 = (-2).(-27)
-3x - 153 = 54
-3x = 54 + 153
-3x = 207
x = -69
b) x - 43 = (35 - x) - 48
x - 43 = 35 - x - 48
x - 43= -x - 13
x = -x - 13 + 43
x = 30 + x
x + x = 30
2x = 30
x = 15
\(2^{x+2}+2^{x-1}+2^{x-2}=152\)
=> \(2^x.2^2+2^x:2+2^x:2^2=152\)
=> \(2^x.2^2+2^x.\frac{1}{2}+2^x.\frac{1}{4}=152\)
=> \(2^x.(4+\frac{1}{2}+\frac{1}{4})=152\)
=> \(2^x.\frac{19}{4}=152\)
=> \(2^x=32\)
=> \(2^x=2^5\)
=> x = 5
Đặt \(2^x=t\left(t>0\right)\)
\(\Rightarrow4t+\frac{1}{2}t+\frac{1}{4}t=152\)
\(\Rightarrow t=32\Rightarrow2^x=32\Rightarrow x=5\)
2x+2 + 2x-1 + 2x-2 = 152
2x.4 + 2x.1/2 + 2x.1/4 = 152
2x.(4+1/2+1/4) = 152
2x.19/4 = 152
2x = 32 = 25
=> x = 5
`a,`
`x*3+7=16`
`=>3x = 16 - 7`
`=> 3x = 9`
`=> x = 9 \div 3`
`=> x = 3`
Vậy, `x = 3`
`b,`
` x- 152 \div 2 = 46?`
`=> x - 76 = 46`
`=> x = 46 + 76`
`=> x = 122`
Vậy, `x = 122.`
`c,`
` 74-2*(x+3)=34`
`=> 2(x + 3) = 74 - 34`
`=> 2(x+2) = 40`
`=> x + 2 = 40 \div 2`
`=> x + 2 = 20`
`=> x = 20 - 2`
`=> x = 18`
Vậy, `x = 18.`
\(152-2.\left(x+1\right)=80\)
\(2.\left(x+1\right)=72\)
\(x+1=36\)
\(x=35\)
\(152-2\left(x+1\right)=80\\ 2\left(x+1\right)=152-80\\ 2\left(x+1\right)=72\\ x+1=72:2\\ x+1=36\\ x=36-1\\ x=35\)