Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(4^{13}+4^{14}+4^{15}+4^{16}=4^{13}\left(1+4\right)+4^{14}\left(1+4\right)=4^{13}.5+4^{14}.5=5\left(4^{13}+4^{14}\right)⋮5\Rightarrow dpcm\)
c) \(2^{10}+2^{11}+2^{12}+2^{13}+2^{14}+2^{15}\)
\(=2^{10}\left(1+2+2^2\right)+2^{13}\left(1+2+2^2\right)\)
\(=2^{10}.7+2^{13}.7=7\left(2^{10}+2^{13}\right)⋮7\Rightarrow dpcm\)
Câu c bạn xem lại đê
- 22.32.5:22.3-32=3.5-32=15-9=6
- 2.52-22.32:32=2.(52-2)=2.(25-2)=46
3. 33.19-33.12=33.(19-12)=33.7=189
4. 3.52-16:22=3.52-24:22=3.25-4=75-4=71
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
a)145-5[8^2-4:15]=145-5[64-4/15]=145-5.956/15=145-956/3=-521/3
b)13^2-3[15-16^2]=13^2-3.-241=169--723=892
a) 7.x - x = 521 : 519 + 3.22 - 70
6x = 25 + 12 - 1
6x = 36
x = 6
b) 7x - 2x = 617 : 615 + 44 : 11
5x = 36 + 4
5x = 40
x = 8
c) 5x + x = 39 - 311 : 39
6x = 39 - 9
6x = 30
x = 5
d) [(6x - 39) : 7]. 4 = 12
(6x - 39) : 7 = 12 : 4
(6x - 39) : 7 = 3
6x - 39 = 3 . 7
6x - 39 = 21
6x = 21 + 39
6x = 60
x = 10
x =
( 15 +x ) : 3 = 315 : 312
=> ( 15 + x ) : 3 = 315 - 12
=> ( 15 + x ) : 3 = 33
=> ( 15 + x ) : 3 = 27
=> 15 + x = 27 . 3
=> 15 + x = 81
=> x = 81 - 15
=> x = 66
Vậy x = 66
a) \(\left(x-1\right)^2=49\)
\(\Rightarrow\left(x-1\right)^2=7^2=\left(-7\right)^2\)
\(\Rightarrow x-1=7\) hoặc \(x-1=-7\)
\(x=7+1=8\) \(x=-7+1=-6\)
Vậy x = 8 hoặc x = - 6
b) \(3\cdot\left(13-x\right)^2=27\)
\(\left(13-x\right)^2=27\div3=9\)
\(\Rightarrow\left(13-x\right)^2=3^2=\left(-3\right)^2\)
\(\Rightarrow13-x=3\) hoặc \(13-x=-3\)
\(x=13-3=10\) \(x=13+3=16\)
Vậy x = 10 hoặc x = 16
c) \(164-\left(15-x\right)^3=100\)
\(\left(15-x\right)^3=164-100=64\)
\(\Rightarrow\left(15-x\right)^3=4^3\)
\(\Rightarrow15-x=4\)
\(x=15-4=11\)
Vậy x = 11
d) \(\left(x+3\right)^3-15=210\)
\(\left(x+3\right)^3=210+15=225\)
\(\Rightarrow\left(x+3\right)^3=...\)
Tương tự mũ lẻ cậu nhé
e) \(x^2\div4=16\)
\(x^2=16\cdot4=64\)
\(\Rightarrow x^2=8^2=\left(-8\right)^2\)
Vậy x = 8 hoặc x = - 8
a/\(\left(x-1\right)^2\)=49
\(\left(x-1\right)^2\)=\(7^2\)
=>x-1=7
x=7+1
x=8
b/3.\(\left(13-x\right)^2\)=27
\(\left(13-x\right)^2\)=27:3
\(\left(13-x\right)^2\)=9
\(\left(13-x\right)^2\)=\(3^2\)
=>13-x=3
x=13-3
x=10
c/164-\(\left(15-x\right)^3\)=100
\(\left(15-x\right)^3\)=164-100
\(\left(15-x\right)^3\)=64
\(\left(15-x\right)^3\)=\(4^3\)
=>15-x=4
x=15-4
x=11
d/\(\left(x+3\right)^3\)-15=210
\(\left(x+3\right)^3\)=210+15
\(\left(x+3\right)^3\)=225
sai đề bài câu d hay sao ý bạn ạ
chỉ có \(\left(x+3\right)^2\)thì mới tính được
e/\(x^2\):4=16
\(x^2\)=16.4
\(x^2\)=64
\(x^2\)=\(8^2\)
=>x=8
\(\left(15+x\right):3=3^{13}:3^{12}\)
\(\Rightarrow\left(15+x\right):3=3\)
\(\Rightarrow15+x=3\cdot3\)
\(\Rightarrow15+x=9\)
\(\Rightarrow x=9-15\)
\(\Rightarrow x=-6\)
\(Toru\)
(15+x):3=3^13:3^12
(15+x):3=3
15+x=9
x=-6