
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a,x=183
b,x=4
Xong rùi!!
Tui lười quá nên ko làm chi tiết mong dựa vào kết quả của tui mà làm đầy đủ thành bài nhoa!!!

mn giải đáp án ra giúp mik nha,mik cảm ơn nhiều!Thank you!

7x = 49
7x = 72
=> x = 2
b) 2 . 4x + 1 = 129
2.4x = 129 - 1
2.4x = 128
4x = 128 : 2
4x = 64
4x = 43
=> x = 3
c) ( x - 5 )3 = 125
( x - 5 )3 = 53
x - 5 = 5
x = 5+5
x = 10
d) ( 4x - 1 )2 = 25 . 9
d) ( 4x - 1 )2 = 225
d) ( 4x - 1 )2 = 152
4x - 1 = 15
4x = 15 + 1
4x = 16
4x = 42
=> x = 2
a) 7x = 49
72 = 49
b) 2 . 4x + 1 = 129
2 . 4x = 129 - 1
2 . 4x = 128
4x = 128 : 2
4x = 64
=> 43
các câu còn lại làm giống như tìm x là đc

1,a) 695- [200+ (11- 12)]
= 695- [200+ (11- 1)]
= 695- [200+ 10]
= 695- 210
= 485
b) (519: 517+ 3): 7
= (52+ 3): 7
= (25+ 3): 7
= 28: 7
= 4
c) 129- 5[29- (6- 12)]
= 129- 5[29- (6- 1)]
= 129- 5[29- 5]
= 129- 5. 24
= 129- 120
= 9
3,a) 2x- 49= 5. 32
2x- 49= 5. 9
2x- 49= 45
2x = 45+ 49
2x = 94
x = 94: 2
x = 47
c) 2x- 15= 17
2x = 17+ 15
2x = 32
2x = 25
=> x = 5
Câu 3b bạn tự làm nhé, xin loiosxn vì không giúp được cả bài.
CHÚC BẠN HỌC GIỎI !!!
MÌNH TÌM RA CÁCH LÀM CÂU 3b RỒI !!!
5x+ 2x= 45+ 20: 15
5x+ 2x= 45+ \(\frac{4}{3}\)
5x+ 2x= \(\frac{139}{3}\)
(5+ 2)x=\(\frac{139}{3}\)
7x =\(\frac{139}{3}\)
x =\(\frac{139}{3}\): 7
x =\(\frac{139}{21}\)
CHÚC BẠN HỌC GIỎI !!!

a, \(x\) \(\times\) \(\dfrac{1}{2}\) - \(\dfrac{3}{4}\) = \(\dfrac{5}{6}\)
\(x\) \(\times\) \(\dfrac{1}{2}\) = \(\dfrac{5}{6}\) + \(\dfrac{3}{4}\)
\(x\) \(\times\) \(\dfrac{1}{2}\) = \(\dfrac{19}{12}\)
\(x\) = \(\dfrac{19}{12}\) : \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{19}{6}\)
b, \(x\) : \(\dfrac{1}{2}\) - \(\dfrac{3}{4}\) = \(\dfrac{5}{6}\)
\(x\): \(\dfrac{1}{2}\) = \(\dfrac{5}{6}\) + \(\dfrac{3}{4}\)
\(x\) : \(\dfrac{1}{2}\) = \(\dfrac{19}{12}\)
\(x\) = \(\dfrac{19}{12}\) \(\times\) \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{19}{24}\)
c, \(x\) \(\times\) \(\dfrac{3}{4}\) + \(x\) \(\times\) \(\dfrac{1}{4}\) = \(\dfrac{7}{8}\)
\(x\) \(\times\) ( \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\)) = \(\dfrac{7}{8}\)
\(x\) \(\times\) 1 = \(\dfrac{7}{8}\)
\(x\) = \(\dfrac{7}{8}\)
d, \(x\times\) \(\dfrac{3}{4}\) - \(x\) \(\times\) \(\dfrac{1}{4}\) = \(\dfrac{7}{8}\)
\(x\) \(\times\) ( \(\dfrac{3}{4}\) - \(\dfrac{1}{4}\)) = \(\dfrac{7}{8}\)
\(x\) \(\times\) \(\dfrac{1}{2}\) = \(\dfrac{7}{8}\)
\(x\) = \(\dfrac{7}{8}\) : \(\dfrac{1}{2}\)
\(x\) = \(\dfrac{7}{4}\)

5 - ( 12 - x ) = 129 - ( 6 + 129 )
5 - 12 + x = 129 - 6 - 129
( -7 ) + x = ( -6)
x = ( - 6 ) + 7
x = 1
Vậy x = 1
5-(12-x)=129-(6+129)
5-(12-x)=129-135
5-(12-x)=-6
12-x =5-(-6)
12-x=11
x=12-11
x=1
\(129-3.\left[\left(x+1\right):4-5\right]=6\)
\(\Rightarrow3\left[\left(x+1\right):4-5\right]=123\)
\(\Rightarrow\left(x+1\right):4-5=123:3\)
\(\Rightarrow\left(x+1\right):4-5=41\)
\(\Rightarrow\left(x+1\right):4=41+5\)
\(\Rightarrow\left(x+1\right):4=46\)
\(\Rightarrow x+1=46.4\)
\(\Rightarrow x+1=184\)
\(\Rightarrow x=183\)