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\((\frac{4}{3}-\frac{1}{4}-\frac{5}{12})\)+2x=\(\frac{8}{5}:\frac{3}{5}\)
=\(\frac{2}{3}\)+2x=\(\frac{8}{3}\)
2x=\(\frac{8}{3}-\frac{2}{3}\)
2x=2
x=2:2
x=1
Vậy x=1
\(\left(\frac{4}{3}-\frac{1}{4}-\frac{5}{12}\right)+2x=\frac{8}{5}:\frac{3}{5}\)
\(\left(\frac{16}{12}-\frac{3}{12}-\frac{5}{12}\right)+2x=\frac{8}{5}.\frac{5}{3}\)
\(\frac{2}{3}+2x=\frac{8}{3}\)
\(2x=\frac{8}{3}-\frac{2}{3}\)
\(2x=2\)
\(x=2:2\)
\(x=1\)
Vậy \(x=1\)
Chúc bạn học thật tốt !!!
Ta có: 2(x-5)-3(x-4)=-6+15(-3)
=>2x-10-3x+12=-6-45
=>-1x+2=-51
=>-1x=-53
=>x=53
Vậy x=53
Tìm x biết : 2 ( x - 5 ) - 3 ( x - 4 ) = - 6 + 15 ( - 3 )
2.(x-5)-3.(x-4)=-6+15.-3
2 (x − 5) − 3 (x − 4) = −51
(2x − 10) − (3x − 12) = −51
2x − 10 − 3x + 12 = −51
(2x − 3x) + (−10 + 12) = −51
−x + 2 = −51 −x = −53
x = 53
Vậy x = 53.
a, -1+3 - 5 + 7 - ...... +97 - 99
[ - 1+ 3] - [ 5 + 7] - .... - [ 95 + 97] - 99
[2 - 12] - ..... - [184 - 192] - 99
còn lại tự giải
a, | x - 3/4 | = 1/2
=>\(\orbr{\begin{cases}x-\frac{3}{4}=\frac{1}{2}\\x-\frac{3}{4}=-\frac{1}{2}\end{cases}}\)
=>\(\orbr{\begin{cases}x=\frac{1}{2}+\frac{3}{4}\\x=-\frac{1}{2}+\frac{3}{4}\end{cases}}\)
=>\(\orbr{\begin{cases}x=\frac{2}{4}+\frac{3}{4}\\x=-\frac{2}{4}+\frac{3}{4}\end{cases}}\)
=>\(\orbr{\begin{cases}x=\frac{5}{4}\\x=\frac{1}{4}\end{cases}}\)
Vậy....
a) \(|x-\frac{3}{4}|=\frac{1}{2}\)
\(< =>\orbr{\begin{cases}x-\frac{3}{4}=\frac{1}{2}\\x-\frac{3}{4}=-\frac{1}{2}\end{cases}}\)
\(< =>\orbr{\begin{cases}x=\frac{1}{2}+\frac{3}{4}\\x=-\frac{1}{2}+\frac{3}{4}\end{cases}}\)
\(< =>\orbr{\begin{cases}x=\frac{5}{4}\\x=\frac{1}{4}\end{cases}}\)
Vay : x = 5/4 hoặc x = 1/4
b)\(saide\)
\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{49\cdot50}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-.....+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{2}-\frac{1}{50}\)
\(=\frac{24}{50}=\frac{12}{25}\)
\(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{49\cdot50}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{49}-\frac{1}{50}\)
\(=\frac{1}{2}-\frac{1}{50}\)
\(=\frac{12}{25}\)