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6/7 - y = 2/3 2/7 : y = 1/2 + 3/10
y = 6/7 - 2/3 2/7 : y = 4/5
y = 4/21 y = 2/7 : 4/5
y = 5/14
a) y = 5/14 : 6/7
y = 5/12
vậy y = 5/12
b) y = 4/9 x 2/3
y = 8/27
vậy t = 8/27
c) y = 1/2 - 3/10
y = 1/5
vậy y = 1/5
d) y = 5/6 - 1/3
y = 1/2
vậy y = 1/2
a: =>y-7/10=4/10
=>y=11/10
b: \(\Leftrightarrow y\cdot\dfrac{4}{9}=\dfrac{3}{2}\)
hay y=27/8
1
a )
( 9407 - 7274 ) : y = 8058 : 34
2133 : y = 237
y = 2133 : 237
y = 9
b )
y x 128 - y x 17 - y x 11 = 576000
y x ( 128 - 17 - 11 ) = 576000
y x 100 = 576000
y = 576000 : 100
y = 5760
2
a )
( 125 x 36 ) : ( 5 x 9 ) =
4500 : 45 =
100
b )
1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10=
( 1/10 + 9/10 ) + ( 2/10 + 8/10 ) + ( 3/10 + 7/10 ) + ( 4/10 + 6/ 10 ) + 5/10=
1 + 1 + 1 + 1 + 0,5 =
4,
Chúc bạn học giỏi nhé !
\(\dfrac{7}{2}-y:\dfrac{4}{5}=\dfrac{3}{4}\)
\(y:\dfrac{4}{5}\) = \(\dfrac{7}{2}\) - \(\dfrac{3}{4}\)
\(y:\dfrac{4}{5}=\dfrac{11}{4}\)
\(y=\dfrac{11}{4}\times\dfrac{4}{5}\)
\(y=\dfrac{11}{5}\)
\(\dfrac{10}{3}-\dfrac{2}{3}:y=\dfrac{1}{9}\)
= \(\dfrac{2}{3}:y=\dfrac{10}{3}-\dfrac{1}{9}\)
= \(\dfrac{2}{3}:y=\dfrac{29}{9}\)
= \(y=\dfrac{2}{3}:\dfrac{29}{9}\)
=\(y=\dfrac{6}{29}\)
\(a,\frac{2}{3}.y=\frac{3}{5}\)
\(y=\frac{3}{5}:\frac{2}{3}\)
\(y=\frac{9}{10}\)
b, \(\frac{2}{5}:y=\frac{7}{10}\)
\(y=\frac{2}{5}:\frac{7}{10}\)\(y=\frac{4}{7}\)
\(c,\frac{4}{5}-y=\frac{5}{7}\)
\(y=\frac{4}{5}-\frac{5}{7}\)
\(y=\frac{3}{35}\)
\(d,y:\frac{2}{5}+1=\frac{7}{2}\)
\(y:\frac{2}{5}=\frac{5}{2}\)
\(y=\frac{5}{2}.\frac{2}{5}\)
\(y=1\)
a/ 2/3*y=3/5 =>y=3/5:2/3=>y=9/10 b/ thôi giác làm để minh lbt
Bài làm :
Y = 11 - 10 + 9 - 8 + 7 - 6 + 5 - 4 + 3 - 2 + 1
Y = 1 + 1 + 1 + 1 + 1 + 1( có 6 chữ số = 1 )
=> Y = 1 x 6 = 6
Vậy Y = 6 nha!
Bài 7:
Số phần kẹo Hùng đã cho Hà và Hồng là:
\(\dfrac{2}{7}+\dfrac{1}{7}=\dfrac{3}{7}\left(phần\right)\)
Hùng còn lại số phần của gói kẹo là:
\(\dfrac{6}{7}-\dfrac{3}{7}=\dfrac{3}{7}\left(phần\right)\)
1:
2 3/4
5 6/5
3 3/9
7 6/8
2:
1/3 + 2/3 + (3/4 + 1/4) = 2
=2
= 4 5/10
1:
a: =8/7-5/88=669/616
b: \(=1+\dfrac{2}{9}\cdot\dfrac{3}{7}-\dfrac{10}{7}=1+\dfrac{2}{21}-\dfrac{10}{7}\)
\(=\dfrac{21+2-30}{21}=\dfrac{-7}{21}=\dfrac{-1}{3}\)
c: \(=\dfrac{11}{3}-\dfrac{6}{7}+4=\dfrac{77-18+84}{21}=\dfrac{143}{21}\)
Bài 2:
a: =>9/4-x=5/11*2=10/11
=>x=9/4-10/11=59/44
b: =>2/9:x=19/21
=>x=2/9:19/21=14/57
\(\frac{2}{7}:y=\frac{10}{21}.\frac{9}{14}\)
\(\frac{2}{7}:y=\frac{15}{49}\)
\(y=\frac{2}{7}:\frac{15}{49}\)
\(y=\frac{2}{7}.\frac{49}{15}\)
\(y=\frac{14}{15}\)
\(y-\frac{1}{3}=\frac{10}{21}:\frac{15}{28}\)
\(y-\frac{1}{3}=\frac{10}{21}.\frac{28}{15}\)
\(y-\frac{1}{3}=\frac{8}{9}\)
\(y=\frac{8}{9}+\frac{1}{3}\)
\(y=\frac{8}{9}+\frac{3}{9}\)
\(y=\frac{11}{9}\)
a) Ta có : \(y-\frac{1}{3}=\frac{10}{21}\div\frac{15}{28}\)
\(\Rightarrow\) \(y-\frac{1}{3}=\frac{8}{9}\)
\(\Rightarrow\) \(y\) \(=\frac{8}{9}+\frac{1}{3}\)
\(\Rightarrow\) \(y\) \(=\frac{11}{9}\)
Vậy \(y=\frac{11}{9}\)
b) Ta có : \(\frac{2}{7}\div y=\frac{10}{21}\times\frac{9}{14}\)
\(\Rightarrow\) \(\frac{2}{7}\div y=\frac{15}{49}\)
\(\Rightarrow\) \(y=\frac{2}{7}\div\frac{15}{49}\)
\(\Rightarrow\) \(y=\frac{14}{15}\)
Vậy \(y=\frac{14}{15}\)
Cbht !!!
10/3-y=7/2-2
10/3-y=3/2
y=10/3-3/2
y=11/6
11/6