Question

[Nguyễn Bùi Diễm Phúc]

1. Tính

căn 2 + căn 3 + căn 8 + căn 16 / căn 2 + căn 3 + căn 4

2.

a. căn x-1=3

b. căn x^2-6x+9=1

c. căn 25x^2-10x+1=5

Giúp với nhaaaaaaaaaaaaaaaaaaaaaaaaa

Answer 1

[Trang]

Bài 2

a . \(\sqrt{x-1}=3\Leftrightarrow x-1=9\Leftrightarrow x=10\)

b . \(\sqrt{x^2-6x+9}=1\Leftrightarrow\sqrt{\left(x-3\right)^2}=1\Leftrightarrow x-3=1\Leftrightarrow x=4\)

c . \(\sqrt{25x^2-10x+1}=5\Leftrightarrow\sqrt{\left(5x-1\right)^2}=5\Leftrightarrow5x-1=5\Leftrightarrow x=\frac{6}{5}\)

Answer 2

[Trang]

Bài 1

\(\sqrt{2}+\sqrt{3}+\sqrt{8}+\frac{\sqrt{16}}{\sqrt{2}}+\sqrt{3}+\sqrt{4}=\sqrt{2}+2\sqrt{3}+2\sqrt{2}+2\sqrt{2}+2\)

\(=5\sqrt{2}+2\sqrt{3}+2\)