Question

[Uzumaki Naruto]

1. a) 2012 x 8 - 8 x 2011 

b) \(\frac{7}{8}\)x 2​\(\frac{2}{3}\)- \(\frac{5}{8}\)X 2\(\frac{2}{3}\)

 Giúp mik đc 1 TICK nhé !

Answer 1

[KAl(SO4)2·12H2O]

a) 2012 x 8 - 8 x 2011

= 8 x (2012 - 2011)

= 8 x 1 

= 8

b) \(\frac{7}{8}.2\frac{2}{3}-\frac{5}{8}.2\frac{2}{3}\)

\(=\frac{7}{8}.\frac{8}{3}-\frac{5}{8}.\frac{8}{3}\)

\(=\frac{8}{3}.\left(\frac{7}{8}-\frac{5}{8}\right)\)

\(=\frac{8}{3}.\frac{2}{8}\)

\(=\frac{16}{6}=\frac{8}{3}\)

Answer 2

[Anna]

1,

a,\(2012.8-8.2011\)

\(=8\left(2012-2011\right)\)

\(=8.1\)

\(=8\)

b.\(\frac{7}{8}.2\frac{2}{3}-\frac{5}{8}.2\frac{2}{3}\)

\(=2\frac{2}{3}.\left(\frac{7}{8}-\frac{5}{8}\right)\)

\(=\frac{8}{3}.\frac{1}{4}\)

\(=\frac{2}{3}\)