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\(\frac{3}{5}x+\frac{1}{2}=\frac{1}{7}\)
\(\Rightarrow\frac{3}{5}x=\frac{1}{7}-\frac{1}{2}\)
\(\Rightarrow\frac{3}{5}x=\frac{-5}{14}\)
\(\Rightarrow x=\frac{-5}{14}\div\frac{3}{5}\)
\(\Rightarrow x=\frac{-25}{42}\)
`1-(5 3/8+x-7 5/24):(-16 2/3)=0`
`=>1-(5+3/8+x-7-5/24):(-50/3)=0`
`=>1=(x-2-11/6):(-50/3)`
`=>1=(x-11/6):(-50/3)`
`=>x-11/6=-50/3`
`=>x=-89/6`
Vậy `x=-89/6`
\(1-\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=0\)
\(\Leftrightarrow1-\left(\dfrac{43}{8}+x-\dfrac{173}{24}\right):\dfrac{50}{3}=0\)
\(\Leftrightarrow1-\left(\dfrac{129}{24}-\dfrac{173}{24}+x\right).\dfrac{3}{50}=0\)
\(\Leftrightarrow1+\dfrac{11}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow\dfrac{17}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow x.\dfrac{3}{50}=\dfrac{17}{6}\)
\(\Leftrightarrow x=\dfrac{425}{9}\)
-Chúc bạn học tốt-
a)\(x+\frac{1}{2}:\left(-\frac{3}{4}\right)=-\frac{5}{4}\)
\(x+-\frac{2}{3}=-\frac{5}{4}\)
\(x=-\frac{5}{4}-\left(-\frac{2}{3}\right)\)
\(x=-\frac{7}{12}\)
Vậy \(x=-\frac{7}{12}\)
b)Câu b mk ko hiểu bn ghi đề sao vậy (5 3/8)
a, => x + \(\frac{-2}{3}=\frac{-5}{4}\)
=>x = \(\frac{15}{8}\)
câu b mik cx làm đc nhưng mik gại ghi lắm
\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)
\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)
Vậy x = 5/19
\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)
Vậy x = 1/2 hoặc x = -6
\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
\(\Leftrightarrow\left(x-3\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
Vậy x = 7 hoặc x = -1
\(1\frac{1}{2}+x=\frac{3}{2}-7\)
<=> \(\frac{3}{2}+x=\frac{-11}{2}\)
<=> \(x=-7\)
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
<=> \(\frac{1}{3}:3x=\frac{-21}{4}\)
<=> \(3x=\frac{-4}{63}\)
<=> \(x=\frac{4}{189}\)
\(\frac{4}{5}.x=\frac{8}{35}\)
<=> \(x=\frac{2}{7}\)
\(\frac{2}{3x}-\frac{1}{4}=\frac{7}{1}\)
<=> \(\frac{2}{3x}=\frac{29}{4}\)
=> \(8=87x\)
<=> \(x=\frac{8}{87}\)
\(\frac{3}{5x}+\frac{1}{2}=\frac{1}{7}\)
<=> \(\frac{3}{5x}=\frac{-5}{14}\)
<=> \(-25x=42\)
<=> \(x=\frac{-42}{25}\)
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16.\frac{2}{3}\right)=0\)
<=> \(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{-32}{3}=0\)
<=> \(\frac{43}{8}+x-\frac{173}{24}=\frac{-32}{3}\)
<=> \(\frac{43}{8}+x=\frac{-83}{24}\)
<=> \(x=\frac{-53}{6}\)
học tốt
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right)\div16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right)\div\frac{50}{3}=0\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right)\div\frac{50}{3}=1-0\)
\(\frac{43}{8}+x-\frac{173}{24}=1\times\frac{50}{3}=\frac{50}{3}\)
\(\frac{43}{8}+x=\frac{50}{3}+\frac{173}{24}=\frac{191}{8}\)
\(\Rightarrow x=\frac{191}{8}-\frac{43}{8}=\frac{148}{8}=\frac{37}{2}\)
f) \(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\)
\(\Rightarrow\dfrac{1}{4}+\dfrac{1}{3}\cdot\dfrac{1}{3}x=-5\)
\(\Leftrightarrow\dfrac{1}{4}+\dfrac{1}{9}x=-5\)
\(\Leftrightarrow9+4x=-180\)
\(\Leftrightarrow4x=-180-9\)
\(\Leftrightarrow4x=-189\)
\(\Rightarrow x=-\dfrac{189}{4}\)