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A,-3/-7+5/19+-4/7
=(-3/-7+-4/7)+5/19
=-1/7+5/19=16/133
B,-13/24+-5/24+7/21
=-3/4+7/21=-5/12
C,-5/13+(-8/13+1)
=(-5/13+-8/13)+1
=-1+1=0
D,2/3+(3/8+-2/3)
=(2/3+-2/3)+3/8
=0+3/8=3/8
E,(-3/4+5/8)+-1/8
=-1/8+1/8=0
a ) 13/20
B)
C..........................................................
minh dang tính
Bài 1: a) \(-2.\left(2x-8\right)+3.\left(4-2x\right)=\left(-72\right)-5.\left(3x-7\right)\)
\(-4x+16+12-6x=-72-15x+35\)
\(-4x-6x+15x=-72+35-16-12\)
\(5x=-65\)
\(x=-\frac{65}{5}\)
\(x=-13\)
b) \(3.\left|2x^2-7\right|=33\)
\(\left|2x^2-7\right|=\frac{33}{3}=11\)
\(\Rightarrow\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}\Rightarrow\orbr{\begin{cases}2x^2=18\\2x^2=-4\end{cases}\Rightarrow}\orbr{\begin{cases}x^2=9\\x^2=-2\left(vl\right)\end{cases}\Rightarrow}\orbr{\begin{cases}x=\pm3\\\end{cases}}}\)
Bài 2:
Ta có: \(2n+1⋮n-3\)
\(2n-6+7⋮n-3\)
\(2\left(n-3\right)+7⋮n-3\)
Vì \(2\left(n-3\right)⋮n-3\)
Để \(2\left(n-3\right)+7⋮n-3\)
Thì \(7⋮n-3\Rightarrow n-3\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
n-3 | -1 | 1 | 7 | -7 |
n | 2 | 4 | 10 | -4 |
Vậy.....
hok tốt!!
a)=-7/21+8/24
=-1/3+1/3
=0
b)=-3/5.(2/7+5/7)+23/5
=-3/5.7/7+23/5
=-3/5.1+23/5
=-3/5+23/5
=20/5=4
c)=75/100-11/2+5/10:5/12+1/4
=3/4-11/2+1/2:5/12+1/4
=3/4+-11/2+1/2.12/5+1/4
=3/4+-22/4+6/5+1/4
=-19/4+6/5+1/4
=(-19/4+1/4)+6/5
=-18/4+6/5
=-9/2+6/5
=-45/10+12/10
=-23/10
a) \(0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\)
\(x.\frac{-1}{6}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{-1}{6}\)
\(x=\frac{-7}{2}\)
b) \(x:4\frac{1}{3}=-2,5\)
\(x:\frac{13}{3}=\frac{-5}{2}\)
\(x=\frac{-5}{2}.\frac{13}{3}\)
\(x=\frac{-65}{6}\)
c) \(5,5x=\frac{13}{15}=\frac{11}{2}x=\frac{13}{5}\)
\(x=\frac{13}{5}:\frac{11}{2}\)
\(x=\frac{26}{55}\)
d) \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)
\(\frac{3x}{7}+1=\frac{-1}{28}.\left(-4\right)\)
\(\frac{3x}{7}+1=\frac{1}{7}\)
\(\frac{3x}{7}=\frac{1}{7}-1\)
\(\frac{3x}{7}=\frac{-6}{7}\)
\(\frac{3x}{7}=\frac{-6}{7}\Rightarrow\frac{3.\left(-2\right)}{7}=\frac{-6}{7}\)
Vậy x = -2
\(0,5x-\frac{2}{3}x=\frac{7}{12}\)\(\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(x.\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\)
a.8x+28-9x+6=24
<=> -x+34=24
<=> -x=24-34
<=> x=10
b. 3-6x-x-18=7
<=> -7x=7+18-3
<=> -7x=22
<=> x=22/-7
1.4x - 5(-3+x)=7
4x - 5(x-3) =7
4x - 5x + 15=7
-1x + 15=7
-1x =-8
=> x =8
2.5(x-3) - 2(x+6)=9
5x - 15 -2x -12=9
5x - 2x -15 - 12=9
5x - 2x=9 + 12 + 15
5x - 2x= 36
3x = 36
=> x = 12
3.4(x-1) - 3(x-2)=15
4x - 4 - 3x + 6=15
4x - 3x =15 - 6 + 4
4x - 3x = 13
=> x = 13
Nhớ mink nhoa pn
\(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
\(\frac{-1}{24}-\left(\frac{1}{4}+\frac{3}{8}\right)\)
\(\frac{-1}{24}-\frac{5}{8}\)
\(\frac{-2}{3}\)
\(-\frac{1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
\(=-\frac{1}{24}-\left(\frac{1}{4}-\frac{1}{2}+\frac{7}{8}\right)\)
\(=-\frac{1}{24}-\frac{5}{8}\)
\(=-\frac{1}{24}-\frac{15}{24}\)
\(=-\frac{16}{24}=-\frac{2}{3}\)