Câu hỏi của Lnh Pnhg

a: \(\dfrac{5}{7}+\dfrac{-3}{11}+\dfrac{2}{7}+\dfrac{-8}{11}\)\(=\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\left(\dfrac{-3}{11}+\dfrac{-8}{11}\right)\)\(=\dfrac{7}{7}-\dfrac{11}{11}=1-1=0\)b: \(\dfrac{5}{11}-\dfrac{3}{7}-\dfrac{4}{7}+\dfrac{6}{11}\)\(=\left(\dfrac{5}{11}+\dfrac{6}{11}\right)-\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)\(=\dfrac{11}{11}-\dfrac{7}{7}=1-1=0\)c: \(\dfrac{9}{13}-\dfrac{3}{8}-\dfrac{5}{8}-\dfrac{22}{13}\)\(=\left(\dfrac{9}{13}-\dfrac{22}{13}\right)+\left(-\dfrac{3}{8}-\dfrac{5}{8}\right)\)\(=-\dfrac{13}{13}-\dfrac{8}{8}=-1-1=-2\)d: \(\dfrac{3}{16}-\dfrac{19}{16}+\dfrac{2}{3}+\dfrac{-8}{3}\)\(=\left(\dfrac{3}{16}-\dfrac{19}{16}\right)+\left(\dfrac{2}{3}-\dfrac{8}{3}\right)\)\(=-\dfrac{16}{16}+\dfrac{-6}{3}=-1-2=-3\)Câu trả lời: a: \(\dfrac{5}{7}+\dfrac{-3}{11}+\dfrac{2}{7}+\dfrac{-8}{11}\)\(=\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\left(\dfrac{-3}{11}+\dfrac{-8}{11}\right)\)\(=\dfrac{7}{7}-\dfrac{11}{11}=1-1=0\)b: \(\dfrac{5}{11}-\dfrac{3}{7}-\dfrac{4}{7}+\dfrac{6}{11}\)\(=\left(\dfrac{5}{11}+\dfrac{6}{11}\right)-\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)\(=\dfrac{11}{11}-\dfrac{7}{7}=1-1=0\)c: \(\dfrac{9}{13}-\dfrac{3}{8}-\dfrac{5}{8}-\dfrac{22}{13}\)\(=\left(\dfrac{9}{13}-\dfrac{22}{13}\right)+\left(-\dfrac{3}{8}-\dfrac{5}{8}\right)\)\(=-\dfrac{13}{13}-\dfrac{8}{8}=-1-1=-2\)d: \(\dfrac{3}{16}-\dfrac{19}{16}+\dfrac{2}{3}+\dfrac{-8}{3}\)\(=\left(\dfrac{3}{16}-\dfrac{19}{16}\right)+\left(\dfrac{2}{3}-\dfrac{8}{3}\right)\)\(=-\dfrac{16}{16}+\dfrac{-6}{3}=-1-2=-3\)