450,3 - ( 21,5 + y : 1/2 ) x 15 = 0
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\(a,x\times15-12,3\times x=81\)
\(x\times\left(15-12,3\right)=81\)
\(x\times2,7=81\)
\(x=80:2,7\)
\(x=30.\)
\(b,x:2,5-4,4=3,8\)
\(x:2,5=3,8+4,4\)
\(x:2,5=8,2\)
\(x=8,2\times2,5\)
\(x=20,5.\)
\(c,37-x+21,5=35,8\)
\(37-x=35,8-21,5\)
\(37-x=14,3\)
\(x=37-14,3\)
\(x=22,7.\)
Áp dụng BĐT phụ \(a^2+b^2\ge\dfrac{1}{2}\left(a+b\right)^2\Leftrightarrow\left(a-b\right)^2\ge0\)
\(A\ge\dfrac{1}{2}\left(x+y+\dfrac{1}{x}+\dfrac{1}{y}\right)^2\ge\dfrac{1}{2}\left(x+y+\dfrac{4}{x+y}\right)^2=\dfrac{1}{2}\left(1+\dfrac{4}{1}\right)^2=\dfrac{25}{2}\)
Dấu "=" \(x=y=\dfrac{1}{2}\)
\(a.\frac{1}{4}+x+x+21,5=36,5\)
\(0,25+21,5+2x=36,5\)\(\)
\(21,75+2x\) \(=36,5\)
\(2x\) \(=36,5-21,75\)
\(x\) \(=14,72\div2=\frac{59}{8}\)
\(b.\frac{3}{5}\times x+x\times2+40=53\)
\(x\times(\frac{3}{5}+2)\) \(=53-40\)
\(x\times\frac{13}{5}\) \(=13\)
\(x\) \(=13\div\frac{13}{5}\)
\(x\) \(=5\)
Học tốt nhé
Câu x ) là bằng - 5 nhé mấy bạn. Làm giúp mình tất cả nhé ! Mình cảm ơn nhiều lắm !
a) \(\left|1-x\right|+\left|y-\frac{2}{3}\right|+\left|x+z\right|=0\)
\(\Leftrightarrow\hept{\begin{cases}1-x=0\\y-\frac{2}{3}=0\\x+z=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=1-0=1\\y=0+\frac{2}{3}=\frac{2}{3}\\z=0-1=-1\end{cases}}}\)
Vậy \(x=1,y=\frac{2}{3},z=-1\)
b) \(\left|\frac{1}{4}-x\right|+\left|x+y+z\right|+\left|\frac{2}{3}+y\right|=0\)
\(\Leftrightarrow\hept{\begin{cases}\frac{1}{4}-x=0\\x+y+z=0\\\frac{2}{3}+y=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=\frac{1}{4}-0=\frac{1}{4}\\x+y+z=0\\y=0+\frac{2}{3}=\frac{2}{3}\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{1}{4}\\z=0-\frac{1}{4}-\frac{2}{3}=\frac{-11}{12}\\y=\frac{2}{3}\end{cases}}}\)
Vậy \(x=\frac{1}{4},y=\frac{-11}{12},z=\frac{2}{3}\)
a . y= 351 : 54 = 6,5
b. (0,215+0,415):7 = 0,63 : 7 = 0,09
Câu 2:
a: Ta có: \(\left|x+\dfrac{19}{5}\right|+\left|y+\dfrac{1890}{1975}\right|+\left|z-2004\right|=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x+\dfrac{19}{5}=0\\y+\dfrac{1890}{1975}=0\\z-2004=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-\dfrac{19}{5}\\y=-\dfrac{378}{395}\\z=2004\end{matrix}\right.\)
b: \(\left|x-\dfrac{1}{2}\right|+\left|y+\dfrac{3}{2}\right|+\left|x-y-z-\dfrac{1}{2}\right|=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}x-\dfrac{1}{2}=0\\y+\dfrac{3}{2}=0\\x-y-z-\dfrac{1}{2}=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{1}{2}\\y=-\dfrac{3}{2}\\z=\dfrac{3}{2}\end{matrix}\right.\)
(21,5+y:1/2)x15=450,3-0
(21,5+y:1/2) =450,3:15(tìm thừa số)
21,5+y:1/2 =30,02
21,5+y =30,02:1/2
y =30-21,5
y =9
450,3 - ( 21,5 + y : 1/2 ) * 15 = 0
=> ( 21,5 + y : 1/2 ) * 15 = 450,3 - 0 = 450,3
=> 21,5 + y : 1/2 = 450,3 : 15 = 30,,02
=> y : 1/2 = 30,02 - 21,5 = 8,52
=> y = 8,52 * 1/2
=> y = 4,26
chúc cậu hok tốt !