x + 20% * x = 7.2
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+\frac{20}{100}+x=7,2\)
\(< =>2x=7,2-\frac{20}{100}=7,2-0,2\)
\(< =>2x=7< =>x=\frac{7}{2}=3,5\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x-20%*x=7.2
=> x .100 % - 20%.x = 7.2
=> x .(100% -20% ) = 7.2
=> x . 80% = 7.2
=> x = 7.2 : 80 %
=> x = 9
\(x-20\%\times x=7,2\)
\(x-\frac{1}{5}\times x=7,2\)
\(x\times\left(1-\frac{1}{5}\right)=7,2\)
\(x\times\frac{4}{5}=7,2\)
\(x=7,2:\frac{4}{5}\)
\(x=9\)
![](https://rs.olm.vn/images/avt/0.png?1311)
X + 0,2 x X = 7,2
1,2 x X = 7,2
X = 7,2 : 1,2
X = 6
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Ta có: \(x+20\%x=7,2\)
<=>\(x+0,2x=7,2\)
<=>\(x\left(1+0,2\right)=7,2\)
<=>\(1,2x=7,2\)
<=>\(x=7,2:1,2\)
<=>\(x=6\)
Vậy:\(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1: =>3^x=81
=>x=4
2: =>2^x=8
=>x=3
3: =>x^3=2^3
=>x=2
4: =>x^20-x=0
=>x(x^19-1)=0
=>x=0 hoặc x=1
5: =>2^x=32
=>x=5
6: =>(2x+1)^3=9^3
=>2x+1=9
=>2x=8
=>x=4
7: =>x^3=115
=>\(x=\sqrt[3]{115}\)
8: =>(2x-15)^5-(2x-15)^3=0
=>(2x-15)^3*[(2x-15)^2-1]=0
=>2x-15=0 hoặc (2x-15)^2-1=0
=>2x-15=0 hoặc 2x-15=1 hoặc 2x-15=-1
=>x=15/2 hoặc x=8 hoặc x=7
1. Tìm số tự nhiên x biết:
1) \(3^x.3=243\)
\(3^x=243:3\)
\(3^x=81\)
\(3^x=3^4\)
\(\Rightarrow x=4\)
_____
2) \(7.2^x=56\)
\(2^x=56:7\)
\(2^x=8\)
\(2^x=2^3\)
\(\Rightarrow x=3\)
_____
3) \(x^3=8\)
\(x^3=2^3\)
\(\Rightarrow x=3\)
_____
4) \(x^{20}=x\)
\(x^{20}-x=0\)
\(x\left(x^{19}-1\right)=0\)
\(\Rightarrow x=0\) hoặc \(x=1\)
5) \(2^x-15=17\)
\(2^x=17+15\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
_____
6) \(\left(2x+1\right)^3=9.81\)
\(\left(2x+1\right)^3=729=9^3\)
\(\rightarrow2x+1=9\)
\(2x=9-1\)
\(2x=8\)
\(x=8:2\)
\(\Rightarrow x=4\)
_____
7) \(x^6:x^3=125\)
\(x^3=125\)
\(x^3=5^3\)
\(\Rightarrow x=5\)
_____
8) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=7\\x=8\end{matrix}\right.\)
_____
9) \(3^{x+2}-5.3^x=36\)
\(3^x.\left(3^2-5\right)=36\)
\(3^x.\left(9-5\right)=36\)
\(3^x.4=36\)
\(3^x=36:4\)
\(3^x=9\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
_____
10) \(7.4^{x-1}+4^{x+1}=23\)
\(\rightarrow7.4^{x-1}+4^{x-1}.4^2=23\)
\(4^{x-1}.\left(7+4^2\right)=23\)
\(4^{x-1}.\left(7+16\right)=23\)
\(4^{x-1}.23=23\)
\(4^{x-1}=23:23\)
\(4^{x-1}=1\)
\(4^{x-1}=4^1\)
\(\rightarrow x-1=0\)
\(x=0+1\)
\(\Rightarrow x=1\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x\div6\times7,2+1,3\times x+x\div2+15=19,95\)
\(\Leftrightarrow x\times\frac{1}{6}\times7,2+1,3\times x+x\times\frac{1}{2}=19,95-15\)
\(\Leftrightarrow x\times1,2+x\times1,3+x\times\frac{1}{2}=4,95\)
\(\Leftrightarrow x\times\left(1,2+1,3+\frac{1}{2}\right)=4,95\)
\(\Leftrightarrow x\times3=4,95\)
\(\Leftrightarrow x=4,95\div3\)
\(\Leftrightarrow x=1,65\)
Vậy x = 1,65
![](https://rs.olm.vn/images/avt/0.png?1311)
x+20%*x=7,2
=> x.100%-20%.x=7,2
=>x.(100%-20%)=7,2
=>x.80% =7,2
=> x=7,2:80%
=> x=9
x + 20%.x = 72
<=> 120% .x = 7,2
x = 7,2 : 120 . 100 = 6