5 + 5 x 7 - 40 = ................................................................................................................................................................................
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2/3 = 2 x 4/ 3 x 4 =8/12
8/14 = 8 : 2/ 14 : 2 =4/7
5/9 = 5 x3/ 9 x 3 =15/37
35/ 40 = 35 : 5/ 40 : 5=7/8
Ta có : -12(x-5) + 7(3-x) = 5
=> (-12)x + 60 +21 - 7x =5
=> x (-12 -7) = 5-60-21
=> (-19)x = -76
=> x = (-76) : (-19)
=> x = 4
Vậy x = 4
720 : [ 41 - ( 2x - 5 ) ] = 40
41 - ( 2x - 5 ) = 720 : 40
41 - ( 2x - 5 ) = 18
2x - 5 = 41 - 18
2x - 5 = 23
2x = 28
x = 14
k nha , minh k lai
\(2.53.12+4.6.87-3.8.40\)
\(=2.53.4.3+4.6.87-3.2.4.40\)
\(=4.6.53+4.6.87-4.6.40\)
\(=4.6.\left(53+87-40\right)\)
\(=4.6.100=2400\)
-12(x-5)+7(3-x)=5
=>(-12x)-(-60)+21-7x=5
=>(-12x-7x)=5-(60+21)=5-84=-76
=>(-19x)=-76=>x=4
Vậy x=4
- 12.( x - 5 ) + 7.( 3 - x ) = 5
=> - 12x + 60 + 21 - 7x = 5
=> ( - 12x - 7x ) + 60 + 21 = 5
=> - 19x + 81 = 5
=> - 19x = 5 - 81
=> - 19x = - 76
=> x = ( - 76 ) : ( - 19 )
=> x = 4
Vậy x = 4
\(a,\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{5}=0\\\dfrac{8}{5}+2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=\dfrac{4}{5}\end{matrix}\right.\)
\(b,\dfrac{x-\dfrac{4}{7}}{x+\dfrac{1}{2}}>0\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x-\dfrac{4}{7}>0\\x+\dfrac{1}{2}>0\end{matrix}\right.\\\left\{{}\begin{matrix}x-\dfrac{4}{7}< 0\\x+\dfrac{1}{2}< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x>\dfrac{4}{7}\\x< -\dfrac{1}{2}\end{matrix}\right.\)
\(c,\dfrac{2x-3}{x+\dfrac{7}{4}}< 0\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}2x-3< 0\\x+\dfrac{7}{4}>0\end{matrix}\right.\\\left\{{}\begin{matrix}2x-3>0\\x+\dfrac{7}{4}< 0\end{matrix}\right.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x< \dfrac{3}{2}\\x >-\dfrac{7}{4}\end{matrix}\right.\\\left\{{}\begin{matrix}x>\dfrac{3}{2}\\x< -\dfrac{7}{4}\end{matrix}\right.\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}-\dfrac{7}{4}< x< \dfrac{3}{2}\\x\in\varnothing\end{matrix}\right.\Leftrightarrow-\dfrac{7}{4}< x< \dfrac{3}{2}\)
=0 nha bn