Tính giá trị biểu thức sau: N = \(\frac{6^6+6^3.3^3+6^3}{-73}\)
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\(N=\frac{6^6+6^3\cdot3^3+3^6}{-73}=\frac{\left(2\cdot3\right)^6+\left(2\cdot3\right)^3\cdot3^3+3^6}{-73}\)
\(=\frac{2^6\cdot3^6+2^3\cdot3^3\cdot3^3+3^6}{-73}=\frac{2^6\cdot3^6+2^3\cdot3^6+3^6}{-73}\)
\(=\frac{3^6\left(2^6+2^3+1\right)}{-73}=\frac{3^6\cdot73}{-73}=-3^6=-729\)
\(N=\dfrac{6^6+6^3.3^3+3^6}{-73}\)
\(\Rightarrow N=\dfrac{\left(2.3\right)^6+\left(2.3\right)^3.3^3+3^6}{-73}\)
\(\Rightarrow N=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}\)
\(\Rightarrow N=\dfrac{3^6\left(2^6+2^3-1\right)}{-73}\)
\(\Rightarrow N=3^6.\left(-1\right)=-729\)
\(\frac{6^6+6^3.3^3+3^6}{-73}\)
\(=\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)
\(=\frac{3^6.73}{-73}\)
\(=3^6.\left(-1\right)=-729\)
\(=\dfrac{3^6\cdot2^6+2^3\cdot3^6+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6=-729\)
\(\frac{6^6+6^3.3^3+3^6}{-73}\)
\(=\frac{3^6.2^6+2^3.3^6+3^6}{-73}\)
\(=\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)
\(=\frac{3^6.73}{-73}\)
\(=-729\)
ket qua =-729
ket qua cua minh chuan ma con nhanh
cac ban k cho minh voi nha
M=\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{25}+4^{15}}=\dfrac{4^{20}\left(2^{20}+1\right)}{4^{15}\left(4^{10}+1\right)}=\dfrac{2^{20}+1}{4^{10}+1}\)
T=\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{9^{10}.5^{30}}{25^{15}.3^{15}}=\dfrac{3^{20}.5^{30}}{5^{30}.3^{15}}=3^5=243\)
\(n=\frac{6^{6+}6^3\times3^3+3^6}{-73}=\frac{2^6\times3^6+3^6\times2^3+3^6}{-73}=\frac{3^6\times\left(2^6+2^3+1\right)}{-73}=\frac{3^6\times73}{-73}=\left(-3\right)^6=3^6\)