Tim x:42—(2×x+32)+18×3bang 6
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a.x-25=0+110
x+25=110
x=85
b.118-x=142-124
118-x=18
x=100
c.3x+22=124-42
3x+22=82
3x=88-22
3x=66
x=22
d.x-2=18
x=20
e.x-32=18.16
x-32=288
x=320
f.19-2x=294:42
19-2x=7
2x=19-7
2x=12
x=6
Dung thi k cho minh nha!!!
42 x 3 + 18 x 32 + 18 x 61
= 6 x 7 x 3 + 18 x 32 + 18 x 61
= 18 x 7 + 18 x 32 + 18 x 61
= 18 x (7 + 32 + 61)
= 18 x 100
= 1800
\(42\times3+18\times32+18\times61\)
\(=6\times7\times3+18\times32+18\times61\)
\(=18\times7+18\times32+18\times61\)
\(=18\times\left(7+32+61\right)\)
\(=18\times100\)
\(=1800\)
`#3107.101107`
a,
$2014^{15} . (2x - 60) = 2014^{16}$
$\Rightarrow 2x - 60 = 2014^{16} \div 2014^{15}$
$\Rightarrow 2x - 60 = 2014$
$\Rightarrow 2x = 2074$
$\Rightarrow x = 1037$
Vậy, `x = 1037`
b,
`x + 18 \div 3^2 = 5.4^2`
`\Rightarrow x + 18 \div 9 = 5.16`
`\Rightarrow x + 9 = 80`
`\Rightarrow x = 80 - 9`
`\Rightarrow x = 71`
Vậy, `x = 71`
c,
`7.(42 - x) = 5^3 + 134`
`\Rightarrow 7.(42 - x) = 125 + 134`
`\Rightarrow 7(42 - x) = 259`
`\Rightarrow 42 - x = 259 \div 7`
`\Rightarrow 42 - x = 37`
`\Rightarrow x = 42 - 37`
`\Rightarrow x = 5`
Vậy, `x = 5.`
\(2,\)
\(a,20-\left[4^2+\left(x-6\right)\right]=90\)
\(\Rightarrow20-16-x+6=90\)
\(\Rightarrow10-x=90\)
\(\Rightarrow x=-80\)
Vậy: \(x=-80\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2^x-6\right)\right]=3^2+4^2\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2^x-6\right)=25\)
\(\Rightarrow24+2^x=40\)
\(\Rightarrow2^x=16\)
\(\Rightarrow x=4\)
Vậy: \(x=4\)
\(2,\)
\(a,20-\left[42+\left(x-6\right)\right]=90\)
\(\Rightarrow20-42-x+6-90=0\)
\(\Rightarrow x=-106\)
Vậy: \(x=-106\)
\(b,\left(x+3\right)\left(2x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\2x-4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-3;2\right\}\)
\(c,1000:\left[30+\left(2x-6\right)\right]=32+42\left(x\in N\right)\)
\(\Rightarrow1000:\left(30+2x-6\right)=74\)
\(\Rightarrow1000:\left(24+2x\right)=74\)
\(\Rightarrow24+2x=\dfrac{500}{37}\)
\(\Rightarrow2x=-\dfrac{388}{37}\)
\(\Rightarrow x=-\dfrac{194}{37}\)
Mà \(x\in N\)
\(\Rightarrow x\in\varnothing\)
Vậy: \(x\in\varnothing\)
a) 32 : 4 : 2 = 8 : 2 = 4
32 : 4 : 2 = 32 : 2 = 16
b) 18 : 2 x 3 = 18 : 6 = 3
18 : 2 x 3 = 9 x 3 = 18