5x-1 +52=30
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Bài 1:
Giải:
Ta có: \(2x=3y\Rightarrow\dfrac{x}{3}=\dfrac{y}{2}\Rightarrow\dfrac{x}{21}=\dfrac{y}{14}\)
\(5x=7z\Rightarrow\dfrac{x}{7}=\dfrac{z}{5}\Rightarrow\dfrac{x}{21}=\dfrac{z}{15}\)
\(\Rightarrow\dfrac{x}{21}=\dfrac{y}{14}=\dfrac{z}{15}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{x}{21}=\dfrac{y}{14}=\dfrac{z}{15}=\dfrac{3x}{63}=\dfrac{7y}{98}=\dfrac{5z}{75}=\dfrac{3x-7y+5z}{63-98+75}=\dfrac{30}{40}=\dfrac{3}{4}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{63}{4}\\y=\dfrac{21}{2}\\z=\dfrac{45}{4}\end{matrix}\right.\)
Vậy...
Bài 2:
Giải:
Ta có: \(3a=2b\Rightarrow\dfrac{a}{2}=\dfrac{b}{3}\Rightarrow\dfrac{a}{10}=\dfrac{b}{15}\)
\(4b=5c\Rightarrow\dfrac{b}{5}=\dfrac{c}{4}\Rightarrow\dfrac{b}{15}=\dfrac{c}{12}\)
\(\Rightarrow\dfrac{a}{10}=\dfrac{b}{15}=\dfrac{c}{12}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{10}=\dfrac{b}{15}=\dfrac{c}{12}=\dfrac{-a-b+c}{-10-15+12}=\dfrac{-52}{-13}=4\)
\(\Rightarrow\left\{{}\begin{matrix}a=40\\b=60\\c=48\end{matrix}\right.\)
Vậy...
Bài 1:
Ta có: \(2x=3y\Rightarrow\dfrac{x}{3}=\dfrac{y}{2}\Rightarrow\dfrac{x}{21}=\dfrac{y}{14}\) (1)
\(5x=7z\Rightarrow\dfrac{x}{7}=\dfrac{z}{5}\Rightarrow\dfrac{x}{21}=\dfrac{y}{15}\) (2)
Từ (1) và (2) suy ra \(\dfrac{x}{21}=\dfrac{y}{14}=\dfrac{z}{15}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
Ta có: \(\dfrac{x}{21}=\dfrac{y}{14}=\dfrac{z}{15}\Rightarrow\dfrac{3x}{63}=\dfrac{7y}{98}=\dfrac{5z}{75}=\dfrac{3x-7y+5z}{63-98+75}=\dfrac{30}{40}=\dfrac{3}{4}\)
Khi đó:
+) \(\dfrac{x}{21}=\dfrac{3}{4}\Rightarrow x=\dfrac{21\cdot3}{4}=\dfrac{63}{4}\)
+) \(\dfrac{y}{14}=\dfrac{3}{4}\Rightarrow y=\dfrac{14\cdot3}{4}=\dfrac{21}{2}\)
+) \(\dfrac{z}{15}=\dfrac{3}{4}\Rightarrow z=\dfrac{15\cdot3}{4}=\dfrac{45}{4}\)
Vậy \(x=\dfrac{63}{4};y=\dfrac{21}{2};z=\dfrac{45}{4}\)
bạn tham khảo nha
a) 85 .12,7 + 5.3.12,7 = 12,7 . ( 85 + 5.3 ) = 12,7 . (85+15) = 12,7 . 100 = 1270
b) 52.143 - 52.39 - 8.26 = 52.143 - 52.39 - 4.2.26 = 52.143 - 52.39 - 4.52 = 52.( 143 -39 - 4 ) = 52 . 100 = 5200
phân tích :
5x - 20y = 5 .(x - 4y)
5x(x-1)-3x.(x-1) = (x-1).(5x-3x) = 2x(x-1) hoặc 5x(x-1)-3x(x-1) = x(x-1)(5-3) = 2x(x-1)
x.(x+y)-5x-5y = x(x+y) - 5 (x+y) = (x+y)(x-5)
\(5^x.5^2=5^{40}\)
\(\Rightarrow5^x=5^{40}:5^2=5^{38}\)
=> x = 38
\(5^x\cdot5^2=5^{40}\)
\(\Leftrightarrow x+2=40\)
hay x=38
1: Ta có: \(x^2-2x-5\)
\(=x^2-2x+1-6\)
\(=\left(x-1\right)^2-6\ge-6\forall x\)
Dấu '=' xảy ra khi x=1
2: ta có: \(3x^2+5x-2\)
\(=3\left(x^2+\dfrac{5}{3}x-\dfrac{2}{3}\right)\)
\(=3\left(x^2+2\cdot x\cdot\dfrac{5}{6}+\dfrac{25}{36}-\dfrac{49}{36}\right)\)
\(=3\left(x+\dfrac{5}{6}\right)^2-\dfrac{49}{12}\ge-\dfrac{49}{12}\forall x\)
Dấu '=' xảy ra khi \(x=-\dfrac{5}{6}\)
Vxe máy = \(\frac{4}{5}\)V ô tô
=> Txe máy = \(\frac{5}{4}\)T ô tô
1 giờ 30 phút = 1,5 giờ.
Thời gian xe máy đi quãng đường AB là:
1,5 x \(\frac{5}{4}\) = 1,875 ( giờ ) = 1 giờ 52 phút 30 giây
Đ/s:......
~ Vậy ta chọn Đáp án: C nha!!!
- Hok T -
\(125:5^x+5^2=26\)
\(\Rightarrow125:5^x+25=26\)
\(\Rightarrow125:5^x=26-25\)
\(\Rightarrow125:5^x=1\)
\(\Rightarrow5^x=125:1\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
a) \(2x^2+20x+52=0\Rightarrow x^2+10x+26=0\Rightarrow\left(x+5\right)^2+1=0\)
\(\Rightarrow\) vô nghiệm
b) ĐK: \(x\ne1;-1\)
\(\dfrac{2x-19}{5x^2-5}-\dfrac{17}{x-1}=\dfrac{8}{1-x}\Rightarrow\dfrac{2x-19}{5\left(x-1\right)\left(x+1\right)}-\dfrac{17}{x-1}+\dfrac{8}{x-1}=0\)
\(\Rightarrow\dfrac{2x-19}{5\left(x-1\right)\left(x+1\right)}-\dfrac{9}{x-1}=0\Rightarrow\dfrac{2x-19-45\left(x+1\right)}{5\left(x-1\right)\left(x+1\right)}=0\)
\(\Rightarrow-43x-64=0\Rightarrow x=-\dfrac{64}{43}\)
a) Ta có: \(\Delta'=100-104=-4< 0\)
Vậy phương trình vô nghiệm.
b) ĐKXĐ: \(x\ne1;x\ne-1\)
\(\Leftrightarrow\dfrac{2x-19}{5\left(x^2-1\right)}=\dfrac{17}{x-1}-\dfrac{8}{x-1}\)
\(\Leftrightarrow\dfrac{2x-19}{5\left(x-1\right)\left(x+1\right)}=\dfrac{9}{x-1}\)
\(\Leftrightarrow\dfrac{2x-19}{5\left(x-1\right)\left(x+1\right)}=\dfrac{45\left(x+1\right)}{5\left(x-1\right)\left(x+1\right)}\)
\(\Rightarrow2x-19=45x+45\)
\(\Leftrightarrow43x=-64\)
\(\Leftrightarrow x=-\dfrac{64}{43}\)(TM)
Vậy phương trình có nghiệm là: \(x=-\dfrac{64}{43}\)
5x-1+52=30
5x + 51 =30
5x-1 + 52 = 30
5x-1 = 30 - 25
5x-1 = 5
x = 5 + 1
x = 6