điền vào dấu hỏi chấm
\(\frac{1}{2}+\frac{1}{2}=?+\frac{1}{3}=?+\frac{1}{4}=?+\frac{1}{5}=?-1=?\)
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hình như cái đề saisai sao ấy bạn ak ??????
tk tui nha
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a) \(\frac{1}{2}+\frac{1}{4}< \frac{3}{4}+\frac{1}{5}\)
b) \(\frac{7}{13}+\frac{2}{9}>\frac{3}{26}+\frac{7}{13}\)
~ GHÉT ..............................~
a) \(\frac{1}{2}+\frac{1}{4}< \frac{3}{4}+\frac{1}{5}\)
b) \(\frac{7}{13}+\frac{2}{9}>\frac{3}{26}+\frac{7}{13}\)
\(1\frac{1}{3}+1\frac{1}{5}.y-\frac{4}{5}=2\frac{4}{5}\)
\(\Rightarrow\frac{4}{3}+\frac{6}{5}.y=2\frac{4}{5}+\frac{4}{5}\)
\(\Rightarrow\frac{4}{3}+\frac{6}{5}.y=2\frac{8}{5}=\frac{18}{5}\)
\(\Rightarrow\frac{6}{5}y=\frac{18}{5}-\frac{4}{3}\)
\(\Rightarrow\frac{6}{5}y=\frac{34}{15}\)
\(\Rightarrow y=\frac{34}{15}:\frac{6}{5}\)
\(\Rightarrow y=\frac{34}{15}.\frac{5}{6}=\frac{17}{9}\)
A=1+1/22 +........+1/1002
=>A<1+1/1*2+1/2*3 +......+1/99*100
=> A< 1+ 1-1/2 +1/2-1/3+......+1/99 -1/100=2-1/100
=>A<2
\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)
1
4/3
19/12
107/60
47/60
\(\frac{1}{2}+\frac{1}{2}=1\)
\(1+\frac{1}{3}=\frac{4}{3}\)
\(\frac{4}{3}+\frac{1}{4}=\frac{19}{12}\)
\(\frac{19}{12}+\frac{1}{5}=\frac{107}{60}\)
\(\frac{107}{60}-1=\frac{47}{60}.\)