2,8. -6 phần 13 - 7,2 - 2,8 . 7 phần 13. Tính nhanh, . là dấu nhân
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a) \(2,8\times19,35-2,8\times19,35\)
\(=2,8\times\left(19,35-19,35\right)\)
\(=2,8\times0\)
\(=0\)
b) \(56,08\times93,23-56,08\times83,23\)
\(=56,08\times\left(93,23-83,23\right)\)
\(=56,08\times10\)
\(=560,8\)
c) \(1,3856\times194-1,3856\times94\)
\(=1,3856\times\left(194-94\right)\)
\(=1,3856\times100\)
\(=138,56\)
d) \(28,524\times3,8+28,524\times6,2\)
\(=28,524\times\left(6,2+3,8\right)\)
\(=28,524\times10\)
\(=285,24\)
c) \(101\times0,128-0,128\)
\(=0,128\times\left(101-1\right)\)
\(=0,128\times100\)
\(=12,8\)
a: =2.8*(19,35-19,35)=0
b: =56,08(93,23-83,23)
=10*56,08=560,8
c: =1,3856(194-94)
=1,3856*100
=138,56
d: =28,524*(3,8+6,2)
=28,524*10
=285,24
e: =0,128*100
=12,8
\(5\times4,9+4,9\times7,2+4,9\times2,8\)
\(=4,9\times\left(5+7,2+2,8\right)\)
\(=4,9\times15\)
\(=73,5\)
5 x 4,9 + 4,9 x 7,2 + 4,9 x 2,8
= 4,9 x (5 + 7,2 + 2,8)
= 4,9 x 15
= 73,5
= 5,6 . 2,8 + 1,7 . 3,3 - 1,1 . 3,9
= 15,68 + 5,61 - 4,29
= 22,19 - 4,29
= 17,9
Tính nhanh
A. 89,26*34,6+89,26*65,4-19,26*49,1-19,26*50,9
B. 62,35*7,2+62,35*2,8-12,35*49,1-12,35*57,1
a: Sửa đề; \(A=\dfrac{7.2:2\cdot28.6+1.43\cdot2\cdot64}{1+3+5+7+...+49-339}\)
\(=\dfrac{3.6\cdot28.6+2.86\cdot64}{1+3+5+...+49-339}\)
\(=\dfrac{2.86\left(64+36\right)}{25^2-339}=\dfrac{286}{286}=1\)
b: =>2(x+7/8)=6*13/4=78/4=39/2
=>x+7/8=39/4
=>x=71/8
`2000+32,4:3xx0,25`
`=2000+8,1:3`
`=2000+2,7`
`=2002,7`
`34,8:x=7,2+2,8`
`34,8:x=10`
`x=34,8:10`
`x=3,48`
Vậy `x=3,48`
a) \(2,8+4,7+7,2+5,3\)
\(=\left(2,8+7,2\right)+\left(4,7+5,3\right)\)
\(=10+10=20\)
b) \(12,34+23,87+7,66+23,13\)
\(=\left(12,34+7,66\right)+\left(23,87+23,13\right)\)
\(=20+47=67\)
c) \(45,09+56,73+54,91+43,27\)
\(=\left(45,09+54,91\right)+\left(56,73+43,27\right)\)
\(=100+100=200\)
d)Sửa đề: \(12,23+24,47+31,18+63,3+68,82\)
\(=\left(12,23+24,47+63,3\right)+\left(31,18+68,82\right)\)
\(=100+100=200\)
\(A,\dfrac{7}{11}+\dfrac{5}{6}-\dfrac{-4}{11}-\dfrac{1}{6}\)
\(= (\dfrac{7}{11}+\dfrac{-4}{11})-(\dfrac{5}{6}-\dfrac{1}{6})\)
\(=\dfrac{3}{11}-\dfrac{2}{3}\)
\(= \dfrac{9}{33}-\dfrac{22}{33}\)
\(= \dfrac{-13}{33}\)
\(B,\dfrac{5}{9}.\dfrac{7}{3}+\dfrac{5}{9}.\dfrac{9}{13}-\dfrac{5}{9}:\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{5}{9}:\dfrac{5}{9}).\dfrac{7}{3}+\dfrac{9}{13}-\dfrac{13}{5}\)
\(=(\dfrac{5}{9}.\dfrac{7}{3})+(\dfrac{9}{13}-\dfrac{13}{5})\)
\(=(\dfrac{5}{9}.\dfrac{21}{9})+(\dfrac{45}{65}-\dfrac{169}{65})\)
\(=\dfrac{35}{27}+\dfrac{-124}{65}\)
\(=\dfrac{2275}{1755}+\dfrac{-3348}{1755}\)
\(=\dfrac{-1073}{1755}\)
Giúp mình với ạ
\(2,8\cdot\dfrac{-6}{13}-7,2-2,8\cdot\dfrac{7}{13}\\ =\left(2,8\cdot\dfrac{-6}{13}-2,8\cdot\dfrac{7}{13}\right)-7,2\\ =2,8\cdot\left(\dfrac{-6}{13}-\dfrac{7}{13}\right)-7,2\\ =2,8\cdot\dfrac{-13}{13}-7,2\\ =-2,8-7,2\\ =-10\)