-3/8 nhân 1/6 + 3/-8 *5/6 +-10/16
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a) Ta có: \(\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}\)
\(=\dfrac{7}{36}+\dfrac{32}{36}+\dfrac{-24}{36}\)
\(=\dfrac{15}{36}=\dfrac{5}{12}\)
b) Ta có: \(\dfrac{-3}{8}\cdot\dfrac{1}{6}+\dfrac{-3}{8}\cdot\dfrac{5}{6}+\dfrac{-10}{16}\)
\(=\dfrac{-3}{8}+\dfrac{-10}{16}\)
\(=\dfrac{-6+\left(-10\right)}{16}=\dfrac{-16}{16}=-1\)
a)
\(\dfrac{-5}{21}+\left(\dfrac{-16}{21}+1\right)=\dfrac{-5}{21}+\dfrac{-16}{21}+1\)=\(-1+1=0\)
`(-5)/21+((-16)/21+1)`
`=(-5)/21-16/21+1`
`=-1+1=0`
`(-3)/8*1/6+3/(-8)*5/6+(-1)/16`
`=-3/8*(1/6+5/6)-10/16`
`=-3/8-10/16`
`=-6/16-10/16=-16/16=-1`
Làm 1 câu
10/3...>...1/3
Mấy câu ssu tự quy đồng hay gì gì đấy!
- \(\dfrac{3}{8}\).\(\dfrac{1}{6}\) + \(\dfrac{3}{-8}\).\(\dfrac{5}{6}\) + \(-\dfrac{10}{16}\)
= - \(\dfrac{3}{8}\).(\(\dfrac{1}{6}\) + \(\dfrac{5}{6}\)) - \(\dfrac{5}{8}\)
= - \(\dfrac{3}{8}\). 1 - \(\dfrac{5}{8}\)
= - \(\dfrac{3}{8}\) - \(\dfrac{5}{8}\)
= -1
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
3.<,>,=
3-5/6....>...1+5/6 41/60-11/60....=....3/8+1/8
2/5+4/15....>...9/10-3/5 1/3-1/12..<....7/8-5/16
$-\frac38\times\frac16+\frac{3}{-8}\times\frac56+\frac{-10}{16}$
$=-\frac38\times(\frac16+\frac56)-\frac58$
$=-\frac38\times1-\frac58$
$=-\frac38-\frac58=-\frac88=-1$
\(\dfrac{-3}{8}\cdot\dfrac{1}{6}+\dfrac{3}{-8}\cdot\dfrac{5}{6}+\dfrac{-10}{16}\\ =\dfrac{-3}{8}\cdot\dfrac{1}{6}+\dfrac{-3}{8}\cdot\dfrac{5}{6}+\dfrac{-5}{8}\\ =\dfrac{-3}{8}\cdot\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+\dfrac{-5}{8}\\ =-\dfrac{3}{8}\cdot1+\dfrac{-5}{8}\\ =\dfrac{-3-5}{8}\\ =-1\)