Question

[Nguyen Hong Ngoc]

 giải phương trình

Answer 1

[Toru]

ĐKXĐ: \(x\ne-5\)

\(\dfrac{x+6}{x+5}+\dfrac{3}{2}=2\)

\(\Leftrightarrow\dfrac{x+6}{x+5}=\dfrac{1}{2}\)

\(\Rightarrow2\left(x+6\right)=1.\left(x+5\right)\)

\(\Leftrightarrow2x+12=x+5\)

\(\Leftrightarrow2x-x=5-12\)

\(\Leftrightarrow x=-7\) (tm ĐKXĐ)

Answer 2

[Nguyễn Lê Phước Thịnh]

ĐKXĐ: \(x\ne-5\)

\(\dfrac{x+6}{x+5}+\dfrac{3}{2}=2\)

=>\(\dfrac{x+6}{x+5}=2-\dfrac{3}{2}=\dfrac{1}{2}\)

=>\(2\left(x+6\right)=x+5\)

=>\(2x+12=x+5\)

=>2x-x=5-12

=>x=-7(nhận)