Tìm số tự nhiên x , biết
\(3x-5^3:5^2=106\) \(12-2x=2^5:2^3\)
\(15x-55=5^3.5^2\)
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a, vì : 32 = 9
=> x - 6 = 3
=> x = 9
b, 720 : [ 41 - ( 2x - 5 ) ] = 40
41 - ( 2x - 5 ) = 720 : 40 = 18
2x - 5 = 41 - 18 = 23
2x = 23 + 5 = 28
x = 28 : 2 = 14
c, ( 4x + 28 ) . 3 + 55 = 35 . 5 = 175
( 4x + 28 ) . 3 = 175 - 55 = 120
4x + 28 = 120 : 3 = 40
4x = 40 - 28 = 12
x = 12 : 4 = 3
**** GIÙM MK NHA , TKS
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
a, 36:(x–5) = 2 2
(x–5) = 9
x = 14
b, [3.(70–x)+5]:2 = 46
[3.(70–x)+5] = 92
70–x = 29
x = 41
c, 450:[41–(2x–5)] = 3 2 .5
41–(2x–5) = 10
2x–5 = 31
2x = 36
x = 18
d, 230+[ 2 4 +(x–5)] = 315. 2018 0
16+(x–5) = 315–230
x–5 = 85–16
x = 69+5
x = 74
e, 2 x + 2 x + 1 = 48
2 x .(2+1) = 48
2 x = 16 = 2 4
x = 4
f, 3 x + 2 + 3 x = 2430
3 x . 3 2 + 1 = 2430
3 x = 2430:10 = 243 = 3 5
x = 5
\(a,\Rightarrow3x\left(x-5\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\\ b,\Rightarrow\left(x-3\right)\left(2x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{2}\end{matrix}\right.\\ c,Đề.sai\\ d,Sửa:\left(x-2\right)^2-16\left(5-2x\right)^2=0\\ \Rightarrow\left[x-2-4\left(5-2x\right)\right]\left[x-2+4\left(5-2x\right)\right]=0\\ \Rightarrow\left(x-2-20+8x\right)\left(x-2+20-8x\right)=0\\ \Rightarrow\left(9x-22\right)\left(18-7x\right)=0\Rightarrow\left[{}\begin{matrix}x=\dfrac{22}{9}\\x=\dfrac{18}{7}\end{matrix}\right.\)
e) 96-5(2x-1)=41
5(2x-1)= 96-41
5(2x-1)=55
2x-1=55:5
2x-1=11
2x=11+1
2x=12
x=12:2
x=6
a ) 18^2 : 9^2 .2^2 +12-12:3
= 4^2 :3 = 16/3
b) 5! +2^10 :2^8
= 120 + 4 = 124
c)28 :[ 117 - ( 117- 4) ] . 7 + 5^3 :125
= 28 : 4 * 7 + 1 = 50
d)3^3. 3^5.3 +2^7 :64
= 3^9 + 2^7 : 2^6 = 3^9 + 1 (tính nhé)
bài 2: tìm x thuôc N biết
a) (2x -2^5). 5^3=2^3.5^3
2x - 2^5 = 2^3
2x = 40
x=20
b) 2^2x -4= 72:3^2
2^2 * x = 12
x= 3
c)3^x + 3^x+1 =108
\(3^x+3^{x+1}=108\) (là thế này ak??)
3^x (1+3) = 108
3^x = 27
x=3
d)(x -3).(3x+5) =0
\(\Rightarrow\orbr{\begin{cases}x-3=0\\3x+5\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-\frac{5}{3}\end{cases}}}\)
\(3x-5^3\div5^2=106\)
\(3x-5=106\)
\(3x=106+5\)
\(3x=111\)
\(x=111\div3\)
\(x=37\)
\(12-2x=2^5\div2^3\)
\(12-2x=2^2\)
\(12-2x=4\)
\(2x=12-4\)
\(2x=8\)
\(x=8\div2=4\)
\(15x-55=5^3.5^2\)
\(15x-55=5^5\)
\(15x-55=3125\)
\(15x=3125+55\)
\(15x=3180\)
\(x=3180\div15\)
\(x=212\)