((4-x).3+51):3-2^2=14
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\(3\cdot\left[\left(4-x\right)3+51\right]\div3-2^2=14\)
\(\Rightarrow3\cdot\left(12-3x+51\right)\div3-4=14\)
\(\Rightarrow3\cdot\left(-3x+12+51\right)\div3=14+4\)
\(\Rightarrow3\cdot\left(-3x+63\right)\div3=18\)
\(\Rightarrow-9x+189=18\cdot3\)
\(\Rightarrow-9x+189=54\)
\(\Rightarrow-9x=54-189\)
\(\Rightarrow-9x=-135\)
\(\Rightarrow x=15\)
3.( (4-\(x\)).3 + 51) : 3 - 22 = 14
(3:3).( (4- \(x\)).3 + 51) - 4 = 14
(4- \(x\)).3 + 51 = 14 + 4
( 4 - \(x\)).3 + 51 = 18
( 4 - \(x\)). 3 = 18 - 51
( 4 - \(x\)).3 = - 33
4 - \(x\) = - 33 : 3
4 - \(x\) = -11
\(x\) = 4 - (-11)
\(x\) = 15
a: \(\Leftrightarrow\dfrac{x-51}{9}-1+\dfrac{x-52}{8}-1=\dfrac{x-53}{7}-1+\dfrac{x-54}{6}-1\)
=>x-60=0
hay x=60
b: \(\Leftrightarrow\left(x-2\right)^2-3\left(x+2\right)=x-14\)
\(\Leftrightarrow x^2-4x+4-3x-6-x+14=0\)
\(\Leftrightarrow x^2-8x+12=0\)
=>(x-2)(x-6)=0
=>x=2(loại) hoặc x=6(nhận)
{ x2 - [ 62 - ( 82 - 9.7)3 - 7.5]3 - 5.3 }3 = 1
{ x2 + [ 36 - (64 - 63)3 - 35]3 - 15}3 = 1
[ x2 - ( 36 - 13 - 35 ) - 15 ]3 = 1
[ x2 - ( 36 - 1 - 35 ) - 15]3 = 1
[ x2 - ( 35 - 35 ) - 15]3 = 1
[ x2 - 0 - 15]3 = 1
( x2 - 15 )3 = 1
<=> ( x2 - 15)3 = 13
=> x2 - 15 = 1
<=> x2 = 16
=> x = 4
a)
\(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
\(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)
\(\frac{1}{3}:x=\frac{-1}{15}\)
\(x=\frac{1}{3}:\frac{-1}{15}\)
\(x=-5\)
b)
\(\frac{10}{3x}+\frac{67}{4}=-13.25\)
\(\frac{10}{3x}+\frac{67}{4}=\frac{-53}{4}\)
\(\frac{10}{3x}=\frac{-53}{4}+\frac{67}{4}\)
\(\frac{10}{3x}=\frac{7}{2}\)
\(\Rightarrow10.2=7.3x\)
\(20=21x\)
\(x=\frac{20}{21}\)
c)
x+30%x=-1.3
x+0.3x=-1.3
x (1+0.3) = -1.3
x . 1.3 = -1.3
x = -1.3 : 1.3
x = 1
d)
\(\left(\frac{14}{5x}-50\right):\frac{2}{3}=51\)
\(\frac{14}{5x}-50=51.\frac{2}{3}\)
\(\frac{14}{5x}-50=34\)
\(\frac{14}{5x}=34+50\)
\(\frac{14}{5x}=84\)
\(84.5x=14\)
420x = 14
\(x=\frac{1}{30}\)
a, \(\frac{2}{3}+\frac{1}{3}:x=\frac{3}{5}\)
=> \(\frac{1}{3}:x=\frac{3}{5}-\frac{2}{3}\)
=>\(\frac{1}{3}:x=\frac{-1}{15}\)
=> \(x=\frac{1}{3}:\frac{-1}{15}\)
=> \(x=\frac{-1}{5}\)
b){x-[52+(35-80.3)3-51]50+14}=20
=>x-[25+(243-240)3-51]50+14=20
=>x-[25+33-51]50+14=20
=>x-[25+27-51]50+14=20
=>x-[52-51]50+14=20
=>x-150+14=20
=>x-1+14=20
=>x-1=20-14
=>x-1=6
=>x=6+1
=>x=7
a){x-[52+(35-80.3)3-51]50+14}=20
=>x-[25+(243-240)3-51]50+14=20
=>x-[25+33-51]50+14=20
=>x-[25+27-51]50+14=20
=>x-[52-51]50+14=20
=>x-150+14=20
=>x-1+14=20
=>x-1=20-14
=>x-1=6
=>x=6+1
=>x=7
\(\left[\left(4-x\right)\cdot3+51\right]:3-2^2=14\)
=>\(\left(4-x+17\right)-4=14\)
=>21-4-x=14
=>17-x=14
=>x=3
X=3