Question

[Bạch Hà An]

B= 0,5+5/7+1/3+0,4+1/6-4/35+9/1945

Answer 1

[hat le]

$0,5+\genfrac{}{}{0ex}{}{1}{3}+0,4+\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{1}{6}-\genfrac{}{}{0ex}{}{4}{35}+\genfrac{}{}{0ex}{}{1}{41}$

$=\genfrac{}{}{0ex}{}{1}{2}+\genfrac{}{}{0ex}{}{1}{3}+\genfrac{}{}{0ex}{}{2}{5}+\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{1}{6}-\genfrac{}{}{0ex}{}{4}{35}+\genfrac{}{}{0ex}{}{1}{41}$

$=\left(\genfrac{}{}{0ex}{}{1}{2}+\genfrac{}{}{0ex}{}{1}{3}+\genfrac{}{}{0ex}{}{1}{6}\right)+\left(\genfrac{}{}{0ex}{}{2}{5}+\genfrac{}{}{0ex}{}{5}{7}-\genfrac{}{}{0ex}{}{4}{35}\right)+\genfrac{}{}{0ex}{}{1}{41}$

$=\left(\genfrac{}{}{0ex}{}{3}{6}+\genfrac{}{}{0ex}{}{2}{6}+\genfrac{}{}{0ex}{}{1}{6}\right)+\left(\genfrac{}{}{0ex}{}{14}{35}+\genfrac{}{}{0ex}{}{25}{35}-\genfrac{}{}{0ex}{}{4}{35}\right)+\genfrac{}{}{0ex}{}{1}{41}$

$=\genfrac{}{}{0ex}{}{3+2+1}{6}+\genfrac{}{}{0ex}{}{14+25-4}{35}+\genfrac{}{}{0ex}{}{1}{41}$

$=1+1+\genfrac{}{}{0ex}{}{1}{41}$

$=2+\genfrac{}{}{0ex}{}{1}{41}$

$=2\genfrac{}{}{0ex}{}{1}{41}=\genfrac{}{}{0ex}{}{83}{41}$
 

Answer 2

[Nguyễn Lê Phước Thịnh]