tính bằng cách thuận tiện : A = 16 x 7 + 16 x 9 - 6 x 16
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\(\dfrac{2021}{2022}.\dfrac{7}{16}+\dfrac{9}{16}.\dfrac{2021}{2022}=\dfrac{2021}{2022}\left(\dfrac{7}{16}+\dfrac{9}{16}\right)=\dfrac{2021}{2022}.1=\dfrac{2021}{2022}\)
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
__
` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
a) \(20\times6\times5\times7\)
\(=\left(20\times5\right)\times6\times7\)
\(=100\times6\times7\)
\(=4200\)
b) \(16\times4\times5\times20\)
\(=16\times4\times100\)
\(=16\times400\)
\(=6400\)
đề bài sai sao ý 9/15 mà nếu 9/ 16 thì ko tính thận tiện đc
\(\dfrac{10}{15}\)x\(\dfrac{9}{16}+\dfrac{7}{15}\)x\(\dfrac{10}{15}\)
=> \(\dfrac{10}{15}\)x\(\left(\dfrac{9}{16}+\dfrac{7}{15}\right)\)
=> \(\dfrac{10}{15}\)x\(\dfrac{247}{240}\)
=> \(\dfrac{247}{360}\)
a) 16 x 8 + 12 x 6
= 4 x 4 x 8 + 4 x 3 x 6
= 4 x 32 + 4 x 18
= 4 x ( 32 + 18 )
= 4 x 50
= 200
b) 16 x 7 + 14 x 2
= 8 x 2 x 7 + 14 x 2
= 8 x 14 + 14 x 2
= ( 8 + 2 ) x 14
= 10 x 14
= 140
c) 8 x 12 - 96
= 8 x 12 - 12 x 8
= 0
a / 16 x 8 + 12 x 6
= ( 8 x 2 ) x ( 8 x 1 ) + ( 6 x 2 ) x ( 6x1 )
= 8 x ( 2 x 1 ) + 6 x ( 2 x 1 )
= 8 x 2 + 6 x 2
= 2 x ( 8 + 6 )
= 2 x 14
= 28
b / 16 x 7 + 14 x 2
= 16 x 7 + ( 7 x 2 ) x2
= 16 x 7 + 7 x 2 x 2
= 7 x ( 16 + 2 ) x 2
= 7 x 18 x2
= 7 x ( 6 x 3 ) x2
= 7 x6 x3 x2
= 7 x 6 x ( 3 x 2 )
= 7 x 6 x6
= ( 7 x 6 ) x ( 6 x 1 )
= 6 x ( 7 x 1 )
= 6 x 7
= 42
c / 8 x 12 - 96
= ( 8 x 12 ) - 96
= 96 - 96
= 0
tớ k chắc cho lắm
=A x (16-9-7): (2+4+6+8+...+20)
=(A x 0): (2+4+6+8+...+20)
=0 x (2+4+6+8+...+20)
=0
A = 16 x 7 + 16 x 9 - 6 x 16
A = 16 x (7 + 9 - 6)
A = 16 x 10
A = 160
16x(7+9-6)
=16x10
=160