Tìm x sao cho x^8/9=729
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a) \(\frac{x^7}{81}=27\)
=> x7 = 27.81
=> x7 = 33.34
=> x7 = 37
=> x = 3
Vậy x = 3
b) \(\frac{x^8}{9}=729\)
=> x8 = 729.9
=> x8 = 36.32
=> x8 = 38 = (-3)8
=> \(x\in\left\{3;-3\right\}\)
Vậy \(x\in\left\{3;-3\right\}\)
x^7/81 = 27 x^8/9 = 729
x^7 : 81= 27 x^8 : 9 = 729
x^7 =27.81 x^8 = 729.9
x^7 =2187 x^8 =6561
x^7 = 3^7 x^8 = 3^8
=> x =3 => x = 3
\(\frac{x^7}{81}=27\Rightarrow x^7=27.81=2187\Rightarrow x=\sqrt[7]{2187}=3\)
\(\frac{x^8}{9}=729\Rightarrow x^8=729.9=6561\Rightarrow x=\sqrt[8]{6561}=3\)
\(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=6561\)
\(\Leftrightarrow x^8=3^8=\left(-3\right)^8\)
\(\Rightarrow x\in\left\{-3;3\right\}\)
a, x-13=184:8
x-13=23
x=23+13
x=36
Vậy x=36
b,x:7=833:7
x:7=119
x=119x7
x=833
Vậy x=833
c, x+5=729:9
x+5=81
x=81-5
x=76
Vậy x=76
d,50-(17-x)=36
17-x=50-36
17-x=14
x=17-14
x=3
Vậy x=3
Hok tốt
`Answer:`
\(\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+...+\left(x+\frac{1}{729}\right)=\frac{4209}{729}\)
\(\Leftrightarrow\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{3^2}\right)+\left(x+\frac{1}{3^3}\right)+...+\left(x+\frac{1}{3^6}\right)=\frac{4209}{729}\)
\(\Leftrightarrow6x+\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)=\frac{4209}{729}\text{(*)}\)
Đặt \(N=\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\)
\(\Leftrightarrow3N=1+\frac{1}{3}+\frac{1}{3^2}+...+\frac{1}{3^5}\)
\(\Leftrightarrow3N-N=\left(1+\frac{1}{3}+\frac{1}{3^2}+..+\frac{1}{3^5}\right)-\left(\frac{1}{3}+\frac{1}{3^2}+\frac{1}{3^3}+...+\frac{1}{3^6}\right)\)
\(\Leftrightarrow2N=1-\frac{1}{3^6}\)
\(\Leftrightarrow2N=\frac{728}{729}\)
\(\Leftrightarrow N=\frac{364}{729}\)
\(\text{(*)}\Leftrightarrow6x+\frac{364}{729}=\frac{4209}{729}\)
\(\Leftrightarrow6x=\frac{3845}{729}\)
\(\Leftrightarrow x=\frac{3845}{4374}\)
\(\frac{x^7}{81}=27\Rightarrow x^7=27.81\Rightarrow x^7=3^3.3^4\Rightarrow x^7=3^7\Rightarrow x=3\)
\(\frac{x^8}{9}=729\Rightarrow x^8=729.9\Rightarrow x^8=3^6.3^2\Rightarrow x^8=3^8\Rightarrow x=3\)
a) Ta có: \(\frac{x^7}{81}=27\)
\(\Rightarrow x^7=27.81=2187\)
Mà \(2187=3^7\) \(\Rightarrow x^7=3^7\Leftrightarrow x=3\)
Vậy x = 3
b) Ta có: \(\frac{x^8}{9}=729\)
\(\Rightarrow x^8=729.9=6561\)
Mà \(6561=3^8\) \(\Rightarrow x^8=3^8\Leftrightarrow x=3\)
Vậy x = 3
CHÚC BẠN HỌC TỐT
b. 9 × ( x + 5) = 729
x + 5 = 729 : 9
x + 5 = 81
x = 81 - 5
x = 76
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\(\frac{x^8}{9}=729\Leftrightarrow x^8=729.9\)
\(\Leftrightarrow x^8=6561\)
\(\Leftrightarrow x^8=\left(\pm3\right)^8\)
\(\Rightarrow x=3;-3\)
Nếu bạn chưa học số âm thì\(x=3\)