cần cứu gấp ạ, em cám ơn rất nhìu :^ :)
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1. bag
2. bunch
3. slice
4. box
5. piece
6. carton
7. can
8. bowl
9. jar
10. bottle
I believe that with the improvement of technology, in the future there will be more modern transportation for humankind. There will be flying cars, trains that goes underwater,... anything we can imagine .Flying cars will make us be able to go with high-speed and less accidents. underwater trains will help us to travel overseas. There might be some disadvantages but those can help clear traffic due to the growth of today's population. Moreover, transport will also improve its security. To sum up, future's mean of transport will be better.
nếu ok thì cho mình like nha, nếu không ok thì không cho. :)
a) Áp suất do nước tác dụng lên đáy cốc:
\(p=d\cdot h=10^4\cdot20\cdot10^{-2}=2000\)N/m3
b) Áp lực lên đáy cốc:
\(F=p\cdot S=2000\cdot\left(\pi\cdot0,02^2\right)=2,51N\)
\(n_{FeS_2}=\dfrac{240}{120}.80\%=1,6\left(mol\right)\)
PTHH: 4FeS2 + 11O2 --to--> 2Fe2O3 + 8SO2
1,6 -------------------------------> 3,2
2SO2 + O2 --to--> 2SO3
3,2 --------------------> 3,2
SO3 + H2O ---> H2SO4
3,2 ----------------> 3,2
\(m_{ddH_2SO_4}=\dfrac{3,2.98}{49\%}=640\left(g\right)\)
o: \(\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}\)
\(=\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+\dfrac{1}{7\cdot9}+\dfrac{1}{9\cdot11}+\dfrac{1}{11\cdot13}\)
\(=\dfrac{1}{2}\left(\dfrac{2}{3\cdot5}+\dfrac{2}{5\cdot7}+\dfrac{2}{7\cdot9}+\dfrac{2}{9\cdot11}+\dfrac{2}{11\cdot13}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{11}-\dfrac{1}{13}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{3}-\dfrac{1}{13}\right)=\dfrac{1}{2}\cdot\dfrac{10}{39}=\dfrac{5}{39}\)
p: \(\dfrac{1}{2}+\dfrac{1}{14}+\dfrac{1}{35}+\dfrac{1}{65}+\dfrac{1}{104}+\dfrac{1}{152}\)
\(=\dfrac{2}{4}+\dfrac{2}{28}+\dfrac{2}{70}+\dfrac{2}{130}+\dfrac{2}{208}+\dfrac{2}{304}\)
\(=\dfrac{2}{1\cdot4}+\dfrac{2}{4\cdot7}+\dfrac{2}{7\cdot10}+\dfrac{2}{10\cdot13}+\dfrac{2}{13\cdot16}+\dfrac{2}{16\cdot19}\)
\(=\dfrac{2}{3}\left(\dfrac{3}{1\cdot4}+\dfrac{3}{4\cdot7}+...+\dfrac{3}{16\cdot19}\right)\)
\(=\dfrac{2}{3}\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+...+\dfrac{1}{16}-\dfrac{1}{19}\right)\)
\(=\dfrac{2}{3}\left(1-\dfrac{1}{19}\right)=\dfrac{2}{3}\cdot\dfrac{18}{19}=\dfrac{2\cdot6}{19}=\dfrac{12}{19}\)