Tìm C:
C = 3/2+3/6+3/12+3/20+3/30+3/42+3/56
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kết quả của biểu thức:
3/6 + 3/12 + 3/20 + 3/30 + 3/42 + 3/56 + 3/72 là:
A. 15/18
B. 7/6
C. 21/6
D. 14/18
A = 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/42 + 1/56
A = 1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8
A = 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8
A = 1 + ( -1/2 + 1/2 ) + ( -1/3 + 1/3 ) + ( -1/4 + 1/4 ) + ( -1/5 + 1/5 ) + ( -1/6 + 1/6 ) + ( -1/7 + 1/7 ) - 1/8
A = 1 + 0 + 0 + 0 + 0 + 0 + 0 - 1/8
A = 1 - 1/8
A = 7/8
* Sửa đề tí nhé
B = 3/2 - 5/6 + 7/12 - 9/20 + 11/30 - 13/42 + 15/56
B = 3/1.2 - 5/2.3 + 7/3.4 - 9/4.5 + 11/5.6 - 13/6.7 + 15/7.8
B = 3 - 3/2 - 5/2 - ( -5/3 ) + 7/3 - 7/4 - 9/4 - ( -9/5 ) + 11/5 - 11/6 - 13/6 - ( -13/7 ) + 15/7 - 15/8
B = 3 - 3/2 - 5/2 + 5/3 + 7/3 - 7/4 - 9/4 + 9/5 + 11/5 - 11/6 - 13/6 + 13/7 + 15/7 - 15/8
B = 3 + ( -3/2 - 5/2 ) + ( 5/3 + 7/3 ) + ( -7/4 - 9/4 ) + ( 9/5 + 11/5 ) + ( -11/6 - 13/6 ) + ( 13/7 + 15/7 ) - 15/8
B = 3 + -4 + 4 + -4 + 4 + -4 + 4 - 15/8
B = 3 + 0 + 0 + 0 - 15/8
B = 3 - 15/8
B = 9/8
a; [6.(- \(\dfrac{1}{3}\))3 - 3.(- \(\dfrac{1}{3}\) + 1)] - ( - \(\dfrac{1}{3}\) - 1)
= [6. \(\dfrac{-1}{3^3}\) - 3.\(\dfrac{2}{3}\)] - ( - \(\dfrac{1}{3}\) - \(\dfrac{3}{3}\))
= [\(\dfrac{-2}{9}\) - 2] + \(\dfrac{4}{3}\)
= [\(\dfrac{-2}{9}\) - \(\dfrac{18}{9}\)] + \(\dfrac{12}{9}\)
= - \(\dfrac{20}{9}\) + \(\dfrac{12}{9}\)
= \(\dfrac{-8}{9}\)
b; (63 + 3.62 + 33): 13
= (216 + 3.36 + 27) : 13
= (216 + 108 + 27): 13
= (324 + 27): 13
= 351 : 13
= 27
A=3/6+3/12+3/20+3/30+3/42+3/56
<=>1/3xA=1/6+1/12+1/20+1/30+1/42+1/56
<=>1/3xA=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8
<=>1/3xA=1/2-1/8=3/8
<=>A=3/8:1/3=9/8
Vậy A=9/8
Đặt 3 chung ra ta dc 1/6+1/12+...+1/56
A=1/2.3+1/4.3+...+1/87.8
A=1/2-1/3+1/3-1/4+...+1/7-1/8
Rút gọn ta dc A=1/2-1/8
tự quy đồng nhé
\(\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+...+\frac{3}{110}\)
\(=3\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{110}\right)\)
\(=3\left(\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+...+\frac{1}{10\cdot11}\right)\)
\(=3\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=3\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(=3\cdot\frac{8}{33}=\frac{8}{11}\)
https://olm.vn/hoi-dap/detail/63463423750.html
vào tham khảo đi mk nhác trình bày
\(m=\frac{3}{2}-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{2}{3}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{5}{4}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{4}{5}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{7}{6}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{6}{7}+\frac{15}{56}-\frac{17}{72}\)
\(m=\frac{9}{8}-\frac{17}{72}\)
\(m=\frac{8}{9}\)
C = 2,625
\(\frac{3}{2}+\frac{3}{6}+\frac{3}{12}+\frac{3}{20}+\frac{3}{30}+\frac{3}{42}+\frac{3}{56}\)
\(\frac{3}{1\cdot2}+\frac{3}{2\cdot3}+\frac{3}{3\cdot4}+\frac{3}{4\cdot5}+\frac{3}{5\cdot6}+\frac{3}{6\cdot7}+\frac{3}{7\cdot8}\)
\(3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\)
\(3\cdot\left(1-\frac{1}{8}\right)\)
\(3\cdot\frac{7}{8}=\frac{21}{8}\)