-35 - 2x = -19
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DN
2
21 tháng 8 2021
\(\dfrac{2x+19}{21}-\dfrac{2x+17}{23}=\dfrac{2x+7}{33}-\dfrac{2x+5}{35}\)
\(\Rightarrow\dfrac{2x+19}{21}-\dfrac{2x+17}{23}-\dfrac{2x+7}{33}+\dfrac{2x+5}{35}=0\)
\(\Rightarrow\left(\dfrac{2x+19}{21}+1\right)-\left(\dfrac{2x+17}{23}+1\right)-\left(\dfrac{2x+7}{33}+1\right)+\left(\dfrac{2x+5}{35}+1\right)=0\)
\(\Rightarrow\dfrac{2x+40}{21}-\dfrac{2x+40}{23}-\dfrac{2x+40}{33}+\dfrac{2x+40}{35}=0\)
\(\Rightarrow\left(2x+40\right)\left(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}\right)=0\)
\(\Rightarrow2x+40=0\Rightarrow x=-20\)( do \(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}>0\))
21 tháng 8 2021
Ta có: \(\dfrac{2x+19}{21}-\dfrac{2x+17}{23}=\dfrac{2x+7}{33}-\dfrac{2x+5}{35}\)
\(\Leftrightarrow\left(2x+40\right)\left(\dfrac{1}{21}-\dfrac{1}{23}-\dfrac{1}{33}+\dfrac{1}{35}\right)=0\)
\(\Leftrightarrow2x+40=0\)
hay x=-20
LM
Lê Minh Vũ
VIP
22 tháng 6 2023
a) \(6x+15\times8=12\times\left(19-x\right)\)
\(6x+120=228-12x\)
\(6x+120-228+12x=0\)
\(18x-108=0\)
\(18x=108\)
\(x=6\)
b) \(160-\left(35\div x+3\right)\times15=15\)
\(160-\left(35\div x+3\right)=1\)
\(35\div x+3=159\)
\(35\div x=156\)
\(x=\dfrac{35}{156}\)
LM
Lê Minh Vũ
VIP
22 tháng 6 2023
c) \(2x-\left(1309\div11-19\right)-2=0\)
\(2x-1309\div11-19=2\)
\(2x-119-19=2\)
\(2x-119=21\)
\(2x=140\)
\(x=70\)
d) \(\left(x-7\right)\times\left(2x-16\right)=0\)
\(x-7=0;2x-16=0\)
\(x=7;2x=16\)
\(x=7;x=8\)
LD
0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
6 tháng 5 2023
Bài giải chi tiết đây em nhé:
\(\dfrac{1}{3}\) + \(\dfrac{1}{15}\) + \(\dfrac{1}{35}\) + \(\dfrac{1}{63}\)+...+ \(\dfrac{1}{\left(2x-1\right)\left(2x+1\right)}\) = \(\dfrac{9}{19}\)
\(\dfrac{1}{2}\)(\(\dfrac{2}{1.3}\) + \(\dfrac{2}{3.5}\)+\(\dfrac{2}{5.7}\)+ \(\dfrac{2}{7.9}\)+...+ \(\dfrac{2}{\left(2x-1\right)\left(2x+1\right)}\)) = \(\dfrac{9}{19}\)
\(\dfrac{1}{2}\)( \(\dfrac{1}{1}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{7}\)+ \(\dfrac{1}{7}\) - \(\dfrac{1}{9}\) +... + \(\dfrac{1}{2x-1}-\dfrac{1}{2x+1}\)) = \(\dfrac{9}{19}\)
\(\dfrac{1}{2}\) ( 1 - \(\dfrac{1}{2x+1}\)) = \(\dfrac{9}{19}\)
1 - \(\dfrac{1}{2x+1}\) = \(\dfrac{9}{19}\) : \(\dfrac{1}{2}\)
1 - \(\dfrac{1}{2x+1}\) = \(\dfrac{18}{19}\)
\(\dfrac{1}{2x+1}\) = \(1-\dfrac{18}{19}\)
\(\dfrac{1}{2x+1}\) = \(\dfrac{1}{19}\)
\(2x+1\) = 19
2\(x\) = 19 - 1
2\(x\) = 18
\(x\) = 18: 2
\(x\) = 9
NT
0
PT
0
P
3
L
22 tháng 11 2019
a)|2x+19|=1
<=>2x+19=-1 or 2x+19=1
<=>2x=-20 or 2x=-18
<=>x=-10 or x=-9
b)|x-35|=6
<=>x-35=-6 or x-35=6
<=>x=29 or x=41
22 tháng 11 2019
a,Ta có I 2x+19 I=1
=> 2x+19=-1,1
Nếu 2x+19 =1
=>2x=20
=>x=10
Nếu 2x+19=-1
=>2x=-18
=>x=-9
Vậy x=-9,10
b, Tương tự câu a. Tự làm đi. Cố lê!!!!!!!!!!
S
3 tháng 1 2023
a) 42 - x = 5
x = 42 - 5
x = 37
b) 15.(x + 4) = 75
x + 4 = 75 : 15
x + 4 = 5
x = 5 - 4
x = 1
d) x + 18 = 12
x = 12 - 18
x = -6
e) 2x - 15 = -19
2x = (-19) + 15
2x = -4
x = -4 : 2
x = -2
f) 36 : (x^3 - 12) = -3
x^3 - 12 = 36 : (-3)
x^3 - 12 = -12
x^3 = 0
=> x = 0
g)x + 15 = 35
x = 35 - 15
x = 20
h) 2x - 13 = 3^2
2x - 13 = 9
2x = 9 + 13
2x = 22
x = 22 : 2
x = 11
\(-35-2x=-19\\\Rightarrow2x=-35-(-19)\\\Rightarrow2x=-35+19\\\Rightarrow2x=-16\\\Rightarrow x=-16:2\\\Rightarrow x=-8\\Vậy:x=-8.\)
−35−2x=−19
⇒2x=−35−(−19)
⇒2x=−35+19
⇒2x=−16
⇒x=−16:2
⇒x=−8
Vậy:x=−8.