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8 tháng 8 2017

a) \(\left(x-2\right)^2=2^2\) 

\(\Rightarrow\left(x-2\right)\left(x-2\right)=2^2\Rightarrow x^2-4x+4=4\)

\(\Rightarrow x^2-4x=0\Rightarrow x\left(x-4\right)=0\Rightarrow\orbr{\begin{cases}x=0\\x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=4\end{cases}}\)

b) \(\left(x+\frac{1}{2}\right)^2=16\)

\(\Rightarrow\left(x+\frac{1}{2}\right)^2=4^2=\left(-4\right)^2\)

\(x+\frac{1}{2}=4\) hoặc \(x+\frac{1}{2}=-4\)

\(\Rightarrow x=4-\frac{1}{2}\) hoặc \(x=-4-\frac{1}{2}\)

\(\Rightarrow x=\frac{7}{2}\) hoặc  x = \(-\frac{9}{2}\)

c) \(\left(2x-3\right)^2-9=27\Rightarrow\left(2x-3\right)^2=36\)

\(\Rightarrow2x-3=6\) hoặc  \(2x-3=-6\)

\(\Rightarrow2x=9\) hoặc \(2x=-3\)

\(\Rightarrow x=\frac{9}{2}\) hoặc \(x=-\frac{3}{2}\)

d) \(\left(2x-3\right)^3=-8\Rightarrow2x-3=-2\)

\(\Rightarrow2x=-2+3=1\Rightarrow x=\frac{1}{2}\)

Chúc bạn hc giỏi,lila ma ri !

25 tháng 9 2020

Rút gọn hả bạn ?

( 3x - 1 )2 - 9( x - 1 )( x + 1 )

= 9x2 - 6x + 1 - 9( x2 - 1 )

= 9x2 - 6x + 1 - 9x2 + 9

= 10 - 6x

( 2x + 3 )( 2x - 3 ) - ( 2x - 1 )2 - ( x - 1 )

= 4x2 - 9 - ( 4x2 - 4x + 1 ) - x + 1

= 4x2 - x - 8 - 4x2 + 4x - 1

= 3x - 9

2( x - 2y )( x + 2y ) + ( x - 2y )2 + ( x + 2y )2

= [ ( x + 2y ) + ( x - 2y ) ]2

= [ x + 2y + x - 2y ]2

= ( 2x )2 = 4x2

27 tháng 7 2023

Bài 6 :

a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)

b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)

c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)

d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)

27 tháng 7 2023

Bài 7 :

a) \(3^x+3^{x+2}=9^{17}+27^{12}\)

\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)

\(\Rightarrow10.3^x=3^{34}+3^{36}\)

\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)

\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)

b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)

\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)

\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)

c) Bài C bạn xem lại đề

d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)

\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)

\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)

\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)

\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)

\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)

31 tháng 8 2020

a, \(\left(x+\frac{4}{3}y^2\right)^2\)

\(=x^2+\frac{8}{3}xy^2+\frac{16}{9}y^4\)

b, \(\left(2x-3y\right)^2\)

\(=4x^2-12xy+9y^2\)

c, \(\left(x^2+2x\right)\left(2x-x^2\right)\)

\(=\left(2x+x^2\right)\left(2x-x^2\right)\)

\(=4x^2-x^4\)

d, \(\left(x+\frac{1}{2}\right)^3\)

\(=x^3+\frac{3}{2}x^2+\frac{3}{4}x+\frac{1}{8}\)

e, \(\left(2x-\frac{6}{5}y\right)^3\)

\(=8x^3-\frac{72}{5}x^2y+\frac{216}{25}xy^2-\frac{216}{125}y^3\)

11 tháng 8 2018

a.(3^2+4^2).x=10^2

(9+16).x     =100

25.x           =100

x                =100:25

x                =4

b.(x-5)^2       =81

x-5             =9

x                =9+5

x                =14

c.(2x+1)^3 = 343

2x+1          = 7

2x              =7-1

2x              =6

x                =6:2

x                = 3

11 tháng 8 2018

(9+16).x=100

25.x=100

x=100:25

x=4

21 tháng 6 2023

1. \(2^x-26=6\)

\(\Rightarrow2^x=6+26\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

2. \(64\cdot4^x=16^8\)

\(\Rightarrow4^3\cdot4^x=4^{16}\)

\(\Rightarrow4^x=4^{16}:4^3\)

\(\Rightarrow4^x=4^{13}\)

\(\Rightarrow x=13\)

3. \(\left(2x-1\right)^4=16\)

\(\Rightarrow\left(2x-1\right)^4=2^4\)

\(\Rightarrow2x-1=2\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)

4. \(\left(2x+1\right)^3=125\)

\(\Rightarrow\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)