Thực hiện phép tính
162+475+173+227+525+438
25.30+5.5.29-25.9
25.2^3_[164_(12_4)^2]
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`a) 162+275+173+227+725+438`
`=(162+438)+(275+725)+(173+227)`
`=600+1000+400`
`=(600+400)+1000`
`=1000+1000=2000`
a ) 5 2 5 − 3 2 5 = 5 − 3 + 2 5 − 2 5 = 2
b ) 6 − 3 4 5 = 5 − 3 + 1 − 4 5 = 2 + 1 5 = 2 1 5
Câu 15:
\(A=2+2^2+2^3+...+2^{100}\)
\(=2\left(1+2\right)+...+2^{99}\left(1+2\right)\)
\(=6\cdot\left(1+...+2^{98}\right)⋮6\)
Đáp án:
Bài 1 :
1) 30.75 + 25.30 – 150
= 30.(75+25) -150
= 30.100 -150
= 3000 -150
= 2850
2) 160 - (4.52 - 3.23)
= 160 – ( 4.25 – 3.8)
= 160 – (100 – 24)
= 160 – 76
= 84
3) [36.4 - 4.(82 - 7.11)2] : 4 - 20220
= [36.4 – 4.(82 – 7.11)2] :4 - 1
= [36.4 – 4.(82 – 77)2] : 4 – 1
= [36.4 – 4.52] : 4 – 1
=[36.4 – 4.25] : 4 – 1
=[4. (36 – 25)] : 4 – 1
= [4. 11] : 4 – 1
=44 : 4 – 1
=11 – 1
= 10
Đây nha bạn!!!
Chúc bạn học tốt!!!
3:
a: \(\dfrac{\left(x-3\right)}{5}=6^2-2^3\cdot4\)
=>\(\dfrac{x-3}{5}=36-8\cdot4=4\)
=>x-3=20
=>x=23
b: \(3^{x+2}+5\cdot2^3=47+\dfrac{18}{4^2-7}\)
=>\(3^{x+2}+5\cdot8=47+\dfrac{18}{16-7}=49\)
=>\(3^{x+2}=9\)
=>x+2=2
=>x=0
c: \(2^{x+1}-2^x=8^2\)
=>\(2^x\cdot2-2^x=2^6\)
=>\(2^x=2^6\)
=>x=6
d: \(\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{99\cdot100}\right)\cdot x^2=99\)
=>\(x^2\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)=99\)
=>\(x^2\cdot\dfrac{99}{100}=99\)
=>\(x^2=100\)
=>\(\left[{}\begin{matrix}x=10\\x=-10\end{matrix}\right.\)
e: \(\left(2x-3\right)^7=\left(2x-3\right)^5\)
=>\(\left(2x-3\right)^5\left[\left(2x-3\right)^2-1\right]=0\)
=>\(\left(2x-3\right)^5\cdot\left(2x-3-1\right)\left(2x-3+1\right)=0\)
=>\(\left(2x-3\right)^5\left(2x-4\right)\left(2x-2\right)=0\)
=>\(\left[{}\begin{matrix}2x-3=0\\2x-4=0\\2x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=2\\x=1\end{matrix}\right.\)
f: \(\left(x-2\right)^{10}=\left(x-2\right)^8\)
=>\(\left(x-2\right)^8\left[\left(x-2\right)^2-1\right]=0\)
=>\(\left(x-2\right)^8\left(x-2-1\right)\left(x-2+1\right)=0\)
=>\(\left(x-2\right)^8\cdot\left(x-3\right)\left(x-1\right)=0\)
=>\(x\in\left\{2;3;1\right\}\)
\(\frac{1}{2}\sqrt{72}+\frac{3}{4}\sqrt{48}+\sqrt{162}-\)\(\sqrt{75}\)
\(=\frac{1}{2}.6\sqrt{2}+\frac{3}{4}.4\sqrt{3}+9\sqrt{2}-5\sqrt{3}\)
\(=3\sqrt{2}+3\sqrt{3}+9\sqrt{2}-5\sqrt{3}\)
\(=12\sqrt{2}-2\sqrt{3}\)
Trước \(\sqrt{75}\)là dấu " - " hay dấu " -- " vậy? Nếu là dấu " -- " thì \(--\sqrt{75}\Rightarrow+\sqrt{75}\)nha
\(a,136⋮2;420⋮2\Rightarrow136+420⋮2\\ 136⋮̸5;420⋮5\Rightarrow136+420⋮̸5\\ b,525⋮5;455⋮5\Rightarrow525-455⋮5\\ 525⋮̸2;455⋮̸2\Rightarrow525-455⋮2\\ c,1\cdot2\cdot3\cdot4\cdot5⋮2;42⋮2\Rightarrow1\cdot2\cdot3\cdot4\cdot5+42⋮2\\ 1\cdot2\cdot3\cdot4\cdot5⋮5;42⋮̸5\Rightarrow1\cdot2\cdot3\cdot4\cdot5+42⋮̸5\)
Bài làm
190 : { 950 : [ 225 - ( 165 - 25 . 2 ) ] } - 20170
= 190 : { 950 : [ 225 - ( 165 - 50 ) ] } - 1
= 190 : { 950 : [ 225 - 115 ] } - 1
= 190 : { 950 : 110 } - 1
= 190 : 95/11 - 1
= 190 x 11/95 - 1
= 22 - 1
= 21
# Học tốt #
525+475+162+438+227+173
1k+600+400
=2k
1250