5.32 + 711: 79-18
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Những phân số có cùng tử số nếu phân số nào có mẫu số lớn hơn thì bé hơn nên 7 11 > 7 9 > 7 5 .
\(\frac{96}{135}\)+\(\frac{153}{199}\)+\(\frac{79}{711}\)và 3
=> 2 < 3
=> \(\frac{96}{135}\)+\(\frac{153}{199}\)+\(\frac{79}{711}\)<3
CHÚC BẠN HỌC GIỎI
K MÌNH NHÉ
a: \(4\cdot3^3-75:5^2\)
\(=4\cdot27-\dfrac{75}{25}\)
=108-3
=105
b: \(7\cdot2^4-16\cdot3\)
\(=16\cdot7-16\cdot3\)
=16(7-3)
=16*4=64
c: \(2^3\cdot17-2^3\cdot14\)
\(=8\cdot17-8\cdot14\)
=8(17-14)
=8*3
=24
d: \(45+\dfrac{54}{3^2}\)
\(=45+\dfrac{54}{9}\)
=45+6
=51
e: \(17\cdot85+15\cdot17-120\)
\(=17\left(85+15\right)-120\)
=1700-120
=1580
f: \(\dfrac{3^{24}}{3^{21}}+2^2\cdot2^3\)
\(=3^3+2^5\)
=27+32
=59
g: \(92+4^3:8\)
=92+64/8
=92+8
=100
h: \(5\cdot2^3+7^{11}:7^9-1^{2023}\)
\(=5\cdot8+49-1\)
=40+48
=88
1: \(23+\left(-13\right)+\left(-50\right)\)
\(=23-13-50\)
=10-50
=-40
2: \(-5+15+\left(-123\right)\)
\(=\left(-5+15\right)-123\)
=10-123
=-113
3: \(5871:\left\{928-\left[\left(-82+247\right)\right]\right\}\cdot5\)
\(=5871-\left\{928+82-247\right\}\cdot5\)
\(=5871-763\cdot5=5871-3815=2056\)
4: \(40-\left(4\cdot5^2-3\cdot2^3\right)\)
\(=40-4\cdot5^2+3\cdot2^3\)
\(=40-4\cdot25+3\cdot8\)
=40-100+24
=64-100
=-36
5: \(6^2\cdot5-7^2+149\)
\(=36\cdot5-49+149\)
\(=180+149-49\)
=180+100
=280
6: \(-210:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]+\left(-2022\right)\)
\(=-210:\left[16+3\cdot\left(6+3\cdot4\right)\right]+\left(-2022\right)\)
\(=-210:\left[16+3\cdot18\right]+\left(-2022\right)\)
\(=-210:70-2022\)
=-3-2022
=-2025
7: \(5\cdot2^3+7^{11}:7^9-2023^0\cdot1^8\)
\(=5\cdot8+7^2-1\)
=40+49-1
=39+49
=88
8: \(400:\left\{5\cdot\left[360-\left(290+2\cdot5^2\right)\right]\right\}\)
\(=400:\left\{5\cdot\left[360-290-2\cdot25\right]\right\}\)
\(=400:\left\{5\cdot20\right\}\)
\(=\dfrac{400}{100}=4\)
9: \(75-\left(3\cdot5^2\right)-4\cdot5^3\)
\(=75-3\cdot25-4\cdot5^3\)
=-4*125
=-500
\(\Rightarrow2x-49=160\\ \Rightarrow2x=160+49=209\\ \Rightarrow x=\dfrac{209}{2}=104,5\)
\(375:\left\{32-\left[4+\left(5.32-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+\left(160-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+118\right]\right\}-14\)
\(=375:\left\{32-122\right\}-14\)
\(=375:\left(-90\right)-14\)
\(=\dfrac{-25}{6}-14\)
\(=\dfrac{-109}{6}\)
\(5\cdot3^2+7^{11}:7^9-1^8\\=5\cdot9+7^2-1\\=45+49-1\\=94-1\\=93\)
thanks