410 . 96 + 312 . 85
______________
613 . 4 - 216 . 312
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Vì \(\frac{312}{216}>1\) mà\(\frac{126}{132}< 1\)
=> \(\frac{312}{216}>\frac{126}{132}\)
ta co : 312/216=312x11/216x11=3432/2376
126/132=126x18/132x18=2268/2376
vi 3434>2268 suy ra 3434/2376>2268/2376
suy ra 312/216>126/132
vay.......
Ta có: \(\dfrac{312}{x}-\dfrac{312}{x+4}=\dfrac{1}{2}\)
\(\Leftrightarrow x\left(x+4\right)=624x+2496-624x\)
\(\Leftrightarrow x^2+4x-2496=0\)
\(\Leftrightarrow\left(x+2\right)^2=2500\)
\(\Leftrightarrow\left[{}\begin{matrix}x=48\\x=-52\end{matrix}\right.\)
312 * 425 + 312 * 574 + 312
= 312 x ( 425 + 574 + 1 )
= 312 x 1000
= 312000
k mik nha
=312 x 425 + 312 x 574 + 312 x 1
= 312 x ( 425 + 574 + 1 )
= 312 x 1000 = 312000
\(312\times425+312\times574+312\)
\(=312\times\left(425+574+1\right)\)
\(=312\times1000\)
\(=312000\)
312 × 425 + 312 × 574 + 312
= 312 × (425 + 574 + 1)
= 312 × 1000
= 312000
A=[(38+17)+125]+29
A=175+29
A=204
B=312.3
B=936
C=1+1+1+1+1
C=5
D=(125:5).(36:9)
D=25.4
D=100
12.34<mx2<3.45+312:26
12.34<mx2<3.45+12
12.34<mx2<15.45
12.34:2<m<15.45:2
6.17<m<7.725
m = tu tinh
`#3107.101107`
\(\dfrac{4^{10}\cdot9^6+3^{12}\cdot8^5}{6^{13}\cdot4-2^{16}\cdot3^{12}}\)
\(=\dfrac{2^{20}\cdot3^{12}+3^{12}\cdot2^{15}}{2^{13}\cdot3^{13}\cdot2^2-2^{16}\cdot3^{12}}\)
\(=\dfrac{3^{12}\cdot\left(2^{20}+2^{15}\right)}{3^{12}\cdot\left(2^{15}\cdot3-2^{16}\right)}\)
\(=\dfrac{2^{20}+2^{15}}{2^{15}\cdot3-2^{16}}\)
\(=\dfrac{2^{15}\cdot\left(2^5+1\right)}{2^{15}\cdot\left(3-2\right)}\)
\(=\dfrac{32+1}{1}\)
\(=33\)