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\(a.\)
\(\dfrac{-21}{39}=\dfrac{-7\cdot3}{3\cdot13}=-\dfrac{7}{13}\)
\(b.\)
\(-\dfrac{21}{39}=-\dfrac{7}{13}=-\dfrac{14}{26}=\dfrac{-28}{52}=-\dfrac{35}{65}=-\dfrac{42}{78}=-\dfrac{49}{91}\)
\(\)
a) \(-\dfrac{21}{39}=-\dfrac{21:3}{39:3}=-\dfrac{7}{13}\)
b) \(-\dfrac{21}{39}=-\dfrac{7}{13}=-\dfrac{14}{26}=-\dfrac{28}{52}=-\dfrac{35}{65}=-\dfrac{42}{78}=-\dfrac{49}{91}\)
Bài Làm
20/48 = 10/24 = 30/72 = 40/96 = 15/36 = 25/60 = 35/84
Chỉ có vậy thui nha !
tkkk nha :)
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\(\frac{20}{48}=\frac{5}{12}\)
\(\frac{5}{12}=\frac{10}{24}=\frac{15}{36}=\frac{20}{48}=\frac{25}{60}=\frac{30}{72}=\frac{35}{84}=\frac{40}{96}\)
\(\Rightarrow\frac{20}{48}=\frac{10}{24}=\frac{15}{36}=\frac{25}{60}=\frac{30}{72}=\frac{35}{84}=\frac{40}{96}\)
a) Giả sử phân số \(\frac{6n-7}{n-1}\) chưa tối tối giản
=> 6n -7 và n - 1 có ước chung là số nguyên tố
Gọi d = ƯC(6n - 7; n - 1)
\(\Leftrightarrow\hept{\begin{cases}6n-7⋮d\\n-1⋮d\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}6n-7⋮d\\6n-6⋮d\end{cases}}\)
\(\Leftrightarrow1⋮d\)
Vì \(d\in N;1⋮d\Leftrightarrow d=1\)
\(\LeftrightarrowƯCLN\left(6n-7;n-1\right)=1\)