Question

[Nguyễn Trần Tuệ Anh]

2x - 3 chia hết cho x - 1
4x + 7 chia hết cho 2x + 1
Em cần gấp ạ , em cảm ơn

Answer 1

[ミ꧁༺༒༻꧂彡]

\(2x-3\text{​​}\text{ ⋮ }x-1\)

\(\Rightarrow2\left(x-1\right)-1\text{ ⋮ }x-1\)

\(\text{mà 2(x-1) ⋮ x-1 }\)\(\Rightarrow1\text{ ⋮ }x-1\)

\(\Rightarrow\)\(x-1\inƯ\left(1\right)=\left\{\pm1\right\}\)

\(x-1\)	\(1\)	\(-1\)
\(x\)	\(2\)	\(0\)

Vậy \(x\in\left\{0;2\right\}\)